牛客 子数组异或和为0的最多划分

淩亂°似流年 2023-06-04 14:54 63阅读 0赞

题目链接:https://www.nowcoder.com/practice/77e9828bbe3c4d4a9e0d49cc7537bb6d?tpId=101&tqId=33110&tPage=1&rp=1&ru=/ta/programmer-code-interview-guide&qru=/ta/programmer-code-interview-guide/question-ranking

题目大意

  略。

分析

  在未排序数组中查找累加和为指定值的最长子数组,与这道题是同样的思路,如果一个数异或了一堆数字后等于他本身,那么这堆数字的异或和为 0。

代码如下

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  1. 1 #include <bits/stdc++.h>
  2. 2 using namespace std;
  3. 3
  4. 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
  5. 5 #define Rep(i,n) for (int i = 0; i < (int)(n); ++i)
  6. 6 #define For(i,s,t) for (int i = (int)(s); i <= (int)(t); ++i)
  7. 7 #define rFor(i,t,s) for (int i = (int)(t); i >= (int)(s); --i)
  8. 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
  9. 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
  10. 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
  11. 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
  12. 12
  13. 13 #define pr(x) cout << #x << " = " << x << " "
  14. 14 #define prln(x) cout << #x << " = " << x << endl
  15. 15
  16. 16 #define LOWBIT(x) ((x)&(-x))
  17. 17
  18. 18 #define ALL(x) x.begin(),x.end()
  19. 19 #define INS(x) inserter(x,x.begin())
  20. 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
  21. 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c
  22. 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
  23. 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
  24. 24
  25. 25 #define ms0(a) memset(a,0,sizeof(a))
  26. 26 #define msI(a) memset(a,0x3f,sizeof(a))
  27. 27 #define msM(a) memset(a,-1,sizeof(a))
  28. 28
  29. 29 #define MP make_pair
  30. 30 #define PB push_back
  31. 31 #define ft first
  32. 32 #define sd second
  33. 33
  34. 34 template<typename T1, typename T2>
  35. 35 istream &operator>>(istream &in, pair<T1, T2> &p) {
  36. 36 in >> p.first >> p.second;
  37. 37 return in;
  38. 38 }
  39. 39
  40. 40 template<typename T>
  41. 41 istream &operator>>(istream &in, vector<T> &v) {
  42. 42 for (auto &x: v)
  43. 43 in >> x;
  44. 44 return in;
  45. 45 }
  46. 46
  47. 47 template<typename T>
  48. 48 ostream &operator<<(ostream &out, vector<T> &v) {
  49. 49 Rep(i, v.size()) out << v[i] << " \n"[i == v.size() - 1];
  50. 50 return out;
  51. 51 }
  52. 52
  53. 53 template<typename T1, typename T2>
  54. 54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
  55. 55 out << "[" << p.first << ", " << p.second << "]" << "\n";
  56. 56 return out;
  57. 57 }
  58. 58
  59. 59 inline int gc(){
  60. 60 static const int BUF = 1e7;
  61. 61 static char buf[BUF], *bg = buf + BUF, *ed = bg;
  62. 62
  63. 63 if(bg == ed) fread(bg = buf, 1, BUF, stdin);
  64. 64 return *bg++;
  65. 65 }
  66. 66
  67. 67 inline int ri(){
  68. 68 int x = 0, f = 1, c = gc();
  69. 69 for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
  70. 70 for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
  71. 71 return x*f;
  72. 72 }
  73. 73
  74. 74 template<class T>
  75. 75 inline string toString(T x) {
  76. 76 ostringstream sout;
  77. 77 sout << x;
  78. 78 return sout.str();
  79. 79 }
  80. 80
  81. 81 inline int toInt(string s) {
  82. 82 int v;
  83. 83 istringstream sin(s);
  84. 84 sin >> v;
  85. 85 return v;
  86. 86 }
  87. 87
  88. 88 //min <= aim <= max
  89. 89 template<typename T>
  90. 90 inline bool BETWEEN(const T aim, const T min, const T max) {
  91. 91 return min <= aim && aim <= max;
  92. 92 }
  93. 93
  94. 94 typedef unsigned int uI;
  95. 95 typedef long long LL;
  96. 96 typedef unsigned long long uLL;
  97. 97 typedef vector< int > VI;
  98. 98 typedef vector< bool > VB;
  99. 99 typedef vector< char > VC;
  100. 100 typedef vector< double > VD;
  101. 101 typedef vector< string > VS;
  102. 102 typedef vector< LL > VL;
  103. 103 typedef vector< VI > VVI;
  104. 104 typedef vector< VB > VVB;
  105. 105 typedef vector< VS > VVS;
  106. 106 typedef vector< VL > VVL;
  107. 107 typedef vector< VVI > VVVI;
  108. 108 typedef vector< VVL > VVVL;
  109. 109 typedef pair< int, int > PII;
  110. 110 typedef pair< LL, LL > PLL;
  111. 111 typedef pair< int, string > PIS;
  112. 112 typedef pair< string, int > PSI;
  113. 113 typedef pair< string, string > PSS;
  114. 114 typedef pair< double, double > PDD;
  115. 115 typedef vector< PII > VPII;
  116. 116 typedef vector< PLL > VPLL;
  117. 117 typedef vector< VPII > VVPII;
  118. 118 typedef vector< VPLL > VVPLL;
  119. 119 typedef vector< VS > VVS;
  120. 120 typedef map< int, int > MII;
  121. 121 typedef unordered_map< int, int > uMII;
  122. 122 typedef map< LL, LL > MLL;
  123. 123 typedef map< string, int > MSI;
  124. 124 typedef map< int, string > MIS;
  125. 125 typedef multiset< int > mSI;
  126. 126 typedef set< int > SI;
  127. 127 typedef stack< int > SKI;
  128. 128 typedef deque< int > DQI;
  129. 129 typedef queue< int > QI;
  130. 130 typedef priority_queue< int > PQIMax;
  131. 131 typedef priority_queue< int, VI, greater< int > > PQIMin;
  132. 132 const double EPS = 1e-8;
  133. 133 const LL inf = 0x7fffffff;
  134. 134 const LL infLL = 0x7fffffffffffffffLL;
  135. 135 const LL mod = 1e9 + 7;
  136. 136 const int maxN = 1e6 + 7;
  137. 137 const LL ONE = 1;
  138. 138 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
  139. 139 const LL oddBits = 0x5555555555555555;
  140. 140
  141. 141 int N, x;
  142. 142 // dp[i] 在arr[1~i]上的最多划分
  143. 143 int dp[maxN];
  144. 144 uMII xorMap; // xorMap[i] = j 表示异或和为 i 最晚出现的位置为 j 位置
  145. 145 int xorSum;
  146. 146
  147. 147 int main() {
  148. 148 //freopen("MyOutput.txt","w",stdout);
  149. 149 //freopen("input.txt","r",stdin);
  150. 150 //INIT();
  151. 151 scanf("%d", &N);
  152. 152 xorMap[0] = 0;
  153. 153 For(i, 1, N) {
  154. 154 scanf("%d", &x);
  155. 155 xorSum ^= x;
  156. 156
  157. 157 if(xorMap.find(xorSum) != xorMap.end()) dp[i] = dp[xorMap[xorSum]] + 1;
  158. 158 dp[i] = max(dp[i], dp[i - 1]);
  159. 159
  160. 160 xorMap[xorSum] = i;
  161. 161 }
  162. 162 printf("%d\n", dp[N]);
  163. 163 return 0;
  164. 164 }

转载于:https://www.cnblogs.com/zaq19970105/p/11392803.html

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