LeetCode 1476. 子矩形查询 JAVA

ゝ一世哀愁。 2022-12-15 14:13 109阅读 0赞

请你实现一个类 SubrectangleQueries ，它的构造函数的参数是一个 rows x cols 的矩形（这里用整数矩阵表示），并支持以下两种操作：

1.  updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)  
    用 newValue 更新以 (row1,col1) 为左上角且以 (row2,col2) 为右下角的子矩形。
2.  getValue(int row, int col)  
    返回矩形中坐标 (row,col) 的当前值。

示例 1：
    
    输入：
    ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"]
    [[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
    输出：
    [null,1,null,5,5,null,10,5]
    解释：
    SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]);  
    // 初始的 (4x3) 矩形如下：
    // 1 2 1
    // 4 3 4
    // 3 2 1
    // 1 1 1
    subrectangleQueries.getValue(0, 2); // 返回 1
    subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
    // 此次更新后矩形变为：
    // 5 5 5
    // 5 5 5
    // 5 5 5
    // 5 5 5 
    subrectangleQueries.getValue(0, 2); // 返回 5
    subrectangleQueries.getValue(3, 1); // 返回 5
    subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
    // 此次更新后矩形变为：
    // 5   5   5
    // 5   5   5
    // 5   5   5
    // 10  10  10 
    subrectangleQueries.getValue(3, 1); // 返回 10
    subrectangleQueries.getValue(0, 2); // 返回 5
    示例 2：
    
    输入：
    ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"]
    [[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
    输出：
    [null,1,null,100,100,null,20]
    解释：
    SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]);
    subrectangleQueries.getValue(0, 0); // 返回 1
    subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100);
    subrectangleQueries.getValue(0, 0); // 返回 100
    subrectangleQueries.getValue(2, 2); // 返回 100
    subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20);
    subrectangleQueries.getValue(2, 2); // 返回 20
     
    
    提示：
    
    最多有 500 次updateSubrectangle 和 getValue 操作。
    1 <= rows, cols <= 100
    rows == rectangle.length
    cols == rectangle[i].length
    0 <= row1 <= row2 < rows
    0 <= col1 <= col2 < cols
    1 <= newValue, rectangle[i][j] <= 10^9
    0 <= row < rows
    0 <= col < cols
    
    来源：力扣（LeetCode）
    链接：https://leetcode-cn.com/problems/subrectangle-queries
    著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

class SubrectangleQueries {
        
        int [][]rectangle;
        public SubrectangleQueries(int[][] rectangle) {
        
            this.rectangle=rectangle;
        }
        
        public void updateSubrectangle(int row1, int col1, int row2, int col2, int newValue) {
        
            for(int i=row1;i<=row2;i++)
            {
        
                for(int j=col1;j<=col2;j++)
                {
        
                    rectangle[i][j]=newValue;
                }
            }
        }
        
        public int getValue(int row, int col) {
        
            return rectangle[row][col];
        }
    }
    
    /**
     * Your SubrectangleQueries object will be instantiated and called as such:
     * SubrectangleQueries obj = new SubrectangleQueries(rectangle);
     * obj.updateSubrectangle(row1,col1,row2,col2,newValue);
     * int param_2 = obj.getValue(row,col);
     */