Python根据经纬度求两点间距离

痛定思痛。 2022-08-20 14:13 366阅读 0赞

Python程序根据经纬度求两点之间距离的两种方法

from math import *
    
    '''计算两点之间直线距离'''
    def get_distance1(lon_a, lat_a, lon_b, lat_b):
        radlat1 = radians(lat_a)
        radlat2 = radians(lat_b)
        a = radlat1 - radlat2
        b = radians(lon_a) - radians(lon_b)
        s = 2 * asin(sqrt(pow(sin(a/2),2) + cos(radlat1) * cos(radlat2)*pow(sin(b/2),2)))
        earth_radius = 6378137
        s = s * earth_radius
        return s
    
    '''计算两点之间直线距离'''
    def get_distance2(lon_a, lat_a, lon_b, lat_b):
        if abs(lon_a - lon_b) < 0.000001 and abs(lat_a - lat_b) < 0.000001:
            return 0
        re = 6378140  # 赤道半径 (m)
        rp = 6356755  # 极半径 (m)
        oblateness = (re - rp) / re  # 地球扁率
        rad_lat_a = radians(lat_a)
        rad_lon_a = radians(lon_a)
        rad_lat_b = radians(lat_b)
        rad_lon_b = radians(lon_b)
        atan_a = atan(rp / re * tan(rad_lat_a))
        atan_b = atan(rp / re * tan(rad_lat_b))
        tmp = acos(sin(atan_a) * sin(atan_b) + cos(atan_a) * cos(atan_b) * cos(rad_lon_a - rad_lon_b))
        if tmp == 0:
            return 0
        c1 = (sin(tmp) - tmp) * (sin(atan_a) + sin(atan_b)) ** 2 / cos(tmp / 2) ** 2
        c2 = (sin(tmp) + tmp) * (sin(atan_a) - sin(atan_b)) ** 2 / sin(tmp / 2) ** 2
        dr = oblateness / 8 * (c1 - c2)
        distance = re * (tmp + dr)
        return distance
    
    def main():
        lon_a = 116.320866
        lat_a = 39.814506
        lon_b = 116.301322
        lat_b = 39.87874
        print(get_distance1(lon_a, lat_a, lon_b, lat_b))
        print(get_distance2(lon_a, lat_a, lon_b, lat_b))
    
    if __name__ == '__main__':
        main()