自动生成Android不同分辨率下的图片

缺乏、安全感 2022-08-14 05:44 185阅读 0赞

Android屏幕分辨率适配的图标处理比较麻烦，让UI做不同尺寸的图片也挺浪费时间的，并且容易出错，于是用Python写了个工具自动化处理图片，UI只需要做好1080\*1920分辨率下的图片就可以了，其它分辨率的图片自动生成。

import os.path
    import sys
    from PIL import Image
    
    """
    自动生成不同分辨率下的App图片
    UI设计1080*1920分辨率图片，放在drawable-xxhdpi目录下，自动生成其它的分辨率图片
    """
    
    __author__ = ['"Xitao":<offbye@gmail.com>']
    
    
    def image_resize(img_file, target, percent):
        """resize image and save to target path
        :param img_file: image file path
        :param target: save path
        :param percent: resize percent
        :return:
        """
        img = Image.open(img_file)
        print(img.size)
        width, height = img.size
        target_img = img.resize((int(width * percent), int(height * percent)), Image.ANTIALIAS)
        target_img.save(target)
        img.close()
        target_img.close()
        print(" save target image to " + target)
    
    
    def path_resize(src, target, percent):
        if not os.path.isdir(src):
            print(src + " must be a dir")
            return -1
    
        os.chdir(src)
        cwd = os.getcwd()
        dirs = os.listdir(cwd)
        for file_name in dirs:
            print file_name
            if file_name.endswith('.9.png'):
                continue
    
            src_file = os.path.join(cwd, file_name)
    
            if not os.path.exists(target):
                os.mkdir(target)
            image_resize(src_file, target + '/' + file_name, percent)
    
    
    def android(res_dir):
        xxhdpi_path = res_dir + "/drawable-xxhdpi/"
    
        if not os.path.isdir(xxhdpi_path):
            print("xxhdpi_path must be a dir")
            return -1
    
        path_resize(xxhdpi_path, res_dir + '/drawable-xhdpi', 0.667)
        path_resize(xxhdpi_path, res_dir + '/drawable-hdpi', 0.444)
        path_resize(xxhdpi_path, res_dir + '/drawable-mdpi', 0.296)
    
    
    if __name__ == "__main__":
        print('please input your androd res dir path')
        print(sys.argv)
        if sys.argv[1]:
            android(sys.argv[1])