C语言实现中缀表达式转后缀表达式并求值

偏执的太偏执、 2022-07-29 11:47 157阅读 0赞

由于是初学时写的代码，所以结构比较混乱  
重构后的代码在这里，供参考：[http://blog.csdn.net/wait\_nothing\_alone/article/details/70184819][http_blog.csdn.net_wait_nothing_alone_article_details_70184819]

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大一菜鸟，初学编程，这是我的第一篇博客，希望能用博客记录我的成长之路。
    初学数据结构，刚接触链表和栈，看到有中缀表达式转后缀的题就试着实现了一下。下面贴上代码。因为使用的是字符型变量，所以只能计算个位数。

/* 堆栈练习——中缀表达式转后缀表达式 */
    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    #include<stdbool.h>
    #define MAX 25
    
    typedef struct node{
        char date;
        struct node *next;
    } LinkStake;
    
    typedef struct node2{
        float date;
        struct node *next;
    } Stake;
    
    typedef struct body{
        char date[MAX];
        int j;
    } Body;
    
    LinkStake *CreatStake();//建立空栈
    int IsEmpty(LinkStake *s);//判断空栈
    void Push(char fuhao, LinkStake *s, Body *p);//压栈
    int Judge(bool flag, char c);//判断优先级
    
    LinkStake *CreatStake()
    {
        LinkStake *s;
        s=malloc(sizeof(struct node));
        s->next = NULL;
        return s;
    }
    
    int IsEmpty(LinkStake *s)
    {
        return(s->next == NULL);
    }
    
    void Push(char fuhao, LinkStake *s, Body *p)
    {
        while(s->next != NULL && Judge(false,fuhao)<Judge(true,s->next->date)){
                LinkStake *t;
                printf("%c", s->next->date);
                p->date[p->j] = s->next->date;
                p->j++;
                t = s->next;
                s->next = t->next;
                free(t);
        }
        if(IsEmpty(s)){
            LinkStake *tmp;
            tmp = malloc(sizeof(struct node));
            tmp->date = fuhao;
            tmp->next = s->next;
            s->next = tmp;
        }
        else if(Judge(false,fuhao)>Judge(true,s->next->date)){
                LinkStake *tmp;
                tmp = malloc(sizeof(struct node));
                tmp->date = fuhao;
                tmp->next = s->next;
                s->next = tmp;
            }
        else if(Judge(false,fuhao) == Judge(true,s->next->date)){
                LinkStake *t;
                t = s->next;
                s->next = t->next;
                free(t);
            }
    }
    
    int Judge(bool flag, char c)
    {
        if(c == '+' || c == '-')
            if(flag) return 3;
            else return 2;
        else if(c == '*' || c == '/')
            if(flag) return 5;
            else return 4;
        else if(c == '(')
            if(flag) return 1;
            else return 6;
        else if(c == ')')
            if(flag) return 6;
            else return 1;
        else return 0;
    }
    
    void PushStake(float c, LinkStake* s)
    {
        Stake *tmp;
        tmp = malloc(sizeof(struct node2));
        tmp->date = c;
        tmp->next = s->next;
        s->next = tmp;
    }
    
    float PopStake(LinkStake *s)
    {
        Stake *t;
        float c;
        t = s->next;
        c = t->date;
        s->next = t->next;
        free(t);
        return c;
    }
    
    int main()
    {
        int i = 0;
        LinkStake *head;
        Body *p = malloc(sizeof(struct body));
        char s[MAX];
        head = CreatStake();
        p->j = 0;
    
        printf("请输入中缀表达式；\n");
        gets(s);
        printf("转换为后缀表达式: \n");
        while(s[i]){
            if(s[i]>='0' && s[i]<='9'){
                printf("%c", s[i]);
                p->date[p->j] = s[i];
                p->j++;
            }
            else Push(s[i],head,p);
            i++;
        }
        while(head->next != NULL){
            printf("%c", head->next->date);
            p->date[p->j++] = head->next->date;
            p->j++;
            LinkStake *t;
            t = head->next;
            head->next = t->next;
            free(t);
        }
        printf("\n");
        printf("计算结果为：\n");
    
        Stake *stake;
        float sum = 0.0, a, b;
        stake = (Stake*)malloc(sizeof(struct node2));
        stake->next = NULL;
        for(int i = 0; i < p->j; i++){
            if(p->date[i]>='0' && p->date[i]<='9')
                PushStake((float)(p->date[i]-'0'), stake);
            else if(p->date[i]=='+'){
                b = PopStake(stake);
                a = PopStake(stake);
                sum = a+b;
                PushStake(sum, stake);
            }
             else if(p->date[i]=='-'){
                b = PopStake(stake);
                a = PopStake(stake);
                sum = a-b;
                PushStake(sum, stake);
            }
             else if(p->date[i]=='*'){
                b = PopStake(stake);
                a = PopStake(stake);
                sum = a*b;
                PushStake(sum, stake);
            }
             else if(p->date[i]=='/'){
                b = PopStake(stake);
                a = PopStake(stake);
                sum = a/b;
                PushStake(sum, stake);
            }
        }
        printf("%.2f", sum);
        return 0;
    }

[http_blog.csdn.net_wait_nothing_alone_article_details_70184819]: http://blog.csdn.net/wait_nothing_alone/article/details/70184819