Where is the Marble? UVA - 10474

爱被打了一巴掌 2022-06-10 14:24 126阅读 0赞

## Where is the Marble? UVA - 10474 ##

Raju and Meena love to play with Marbles. They have got a lot of  
marbles with numbers written on them. At the beginning, Raju would  
place the marbles one after another in ascending order of the numbers  
written on them. Then Meena would ask Raju to find the first marble  
with a certain number. She would count 1…2…3. Raju gets one point  
for correct answer, and Meena gets the point if Raju fails. After some  
fixed number of trials the game ends and the player with maximum  
points wins. Today it’s your chance to play as Raju. Being the smart  
kid, you’d be taking the favor of a computer. But don’t underestimate  
Meena, she had written a program to keep track how much time you’re  
taking to give all the answers. So now you have to write a program,  
which will help you in your role as Raju.  
Input  
There can be multiple test cases. Total no of test cases is less than 65. Each test case consists begins  
with 2 integers: N the number of marbles and Q the number of queries Mina would make. The next  
N lines would contain the numbers written on the N marbles. These marble numbers will not come  
in any particular order. Following Q lines will have Q queries. Be assured, none of the input numbers  
are greater than 10000 and none of them are negative.  
Input is terminated by a test case where N = 0 and Q = 0.  
Output  
For each test case output the serial number of the case.  
For each of the queries, print one line of output. The format of this line will depend upon whether  
or not the query number is written upon any of the marbles. The two different formats are described  
below:  
• ‘x found at y’, if the first marble with number x was found at position y. Positions are numbered  
1, 2, … , N.  
• ‘x not found’, if the marble with number x is not present.  
Look at the output for sample input for details.  
Sample Input  
4 1  
2  
3  
5  
1  
5  
5 2  
1  
3  
3  
3  
1  
2  
3  
0 0  
Sample Output  
CASE\# 1:  
5 found at 4  
CASE\# 2:  
2 not found  
3 found at 3

**AC Code:**

#include <iostream>
    #include <cstdio>
    #include <algorithm>
    #include <vector>
    using namespace std;
    
    int main(){
      int caseNumber = 0;
      int N, Q;
      int marbles[10005];
      while( scanf("%d%d", &N, &Q) != EOF && N != 0 && Q != 0 ){
        printf("CASE# %d:\n", ++caseNumber);
        for( int i = 0 ; i < N ; ++i ){
          scanf("%d", &marbles[i]);
        }
    
        sort(marbles, marbles+N);
    
        int query;
        for( int i = 0 ; i < Q ; ++i ){
          scanf("%d", &query);
          int *position = lower_bound( marbles, marbles+N, query );
          if( position == marbles+N || *position != query ){
            printf("%d not found\n", query);
          }
          else{
            printf("%d found at %d\n", query, (int)(position-marbles)+1);
          }
        }
      }
    
      return 0;
    }