Python实现Pat 1035. Password (20)

古城微笑少年丶 2022-06-04 08:39 154阅读 0赞

### [题目][Link 1] ###

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase). One solution is to replace 1 (one) by @, 0 (zero) by %, l by L, and O by o. Now it is your job to write a program to check the accounts generated by the judge, and to help the juge modify the confusing passwords.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N (<= 1000), followed by N lines of accounts. Each account consists of a user name and a password, both are strings of no more than 10 characters with no space.

Output Specification:

For each test case, first print the number M of accounts that have been modified, then print in the following M lines the modified accounts info, that is, the user names and the corresponding modified passwords. The accounts must be printed in the same order as they are read in. If no account is modified, print in one line “There are N accounts and no account is modified” where N is the total number of accounts. However, if N is one, you must print “There is 1 account and no account is modified” instead.

Sample Input 1:

3  
Team000002 Rlsp0dfa  
Team000003 perfectpwd  
Team000001 R1spOdfa  
Sample Output 1:  
2  
Team000002 RLsp%dfa  
Team000001 R@spodfa  
Sample Input 2:  
1  
team110 abcdefg332  
Sample Output 2:  
There is 1 account and no account is modified  
Sample Input 3:  
2  
team110 abcdefg222  
team220 abcdefg333  
Sample Output 3:  
There are 2 accounts and no account is modified

### 解答 ###

N=int(input())
    users=[]
    for i in range(N):
        a,b=input().split(' ')
        #replace方法只能替换单个字符串，但字符大小可以不同
        #例如b='this'.replace('is','eez'),结果为theez
        #maketrans和translate都是str的方法，可以一一对应地替换
        table =b.maketrans('10lO','@%Lo')
        b_m=b.translate(table)
        if b!=b_m:
            users.append([a,b_m])
    len_m=len(users)
    if len_m:
        print (len(users))
        for u in users:
            print (u[0],u[1])
    elif N!=1:
        print ('There are %d accounts and no account is modified'%N)
    else:
        print('There is 1 account and no account is modified')

![这里写图片描述][SouthEast]

[Link 1]: https://www.patest.cn/contests/pat-a-practise/1034
[SouthEast]: /images/20220604/6e04924cd13b457a86ebbc0b5c0a1c77.png