java后台登陆密码复杂性验证

深碍√TFBOYSˉ_ 2022-04-04 03:19 548阅读 0赞

此代码中没有包含对密码长度验证，可以在 获取密码处进行验证，代码中的if(StringHandle.isNotEmpty(newPwd) && newPwd.length() > 0)判断可以去掉，在调用该方法钱验证，该方法时验证获取到的密码是否为空、null，以及长度是否大于0，否则遍历会报错，根据代码返回的字符串来判断该如何在前台提示

/**
    * 密码复杂性进行验证 可以包含以下( 0~9,a~z,A~Z,(,),-,.,: )
    * @return
    */
        public String isPwdComplex(String newPwd) {
        	int digit = 0;
        	int lowerString = 0;
        	int upperString = 0;
        	int special = 0;
            Boolean flag = true;
        	if(StringHandle.isNotEmpty(newPwd) && newPwd.length() > 0){
        		for(int i = 0; i < newPwd.length(); i++){
        			if(newPwd.charAt(i) >= '0' && newPwd.charAt(i) <= '9') {
        				digit = 1;
        			} else if (newPwd.charAt(i) >= 'a' && newPwd.charAt(i) <= 'z'){
        				lowerString = 1;
        			} else if (newPwd.charAt(i) >= 'A' && newPwd.charAt(i) <= 'Z'){
        				upperString = 1;
        			}else if(newPwd.charAt(i) == '(' || newPwd.charAt(i) == ')' || newPwd.charAt(i) == '-' || newPwd.charAt(i) == '.' || newPwd.charAt(i) == ':') {
        				special = 1;
        			} else {
        				flag = false; // 包含特殊字符，但是不被允许
        			}
        		}
        		if(digit != 1 || lowerString + upperString == 0){ // 必须由字母数字组成
        			return "incomplete";  
        		} else if (digit == 1 && lowerString + upperString != 0 && flag == true) { // 包含不被允许的特殊字符
        			return "correct";
        		} else {  // 验证通过
        			return "nonsupport";
        		}
        	} else {
        		return "";
        	}
        }

最终的代码是：

1、在该方法中调用验证

String newpassword = ServletActionContext.getRequest().getParameter("newpassword");
    		if(StringHandle.isNotEmpty(newpassword) && newpassword.length() >= 6) {
    			String verificationResults = isPwdComplex(newpassword);
    			if(id!=""&&!id.equals("") && "correct".equals(verificationResults)){
    				user=userService.getUserById(Integer.parseInt(id));
    				user.setPassword((MD5.getMD5(newpassword.getBytes())));
    				userService.addUser(user);
    				logService.addOperationLog("管理员修改用户密码,id为："+user.getUserId());
    				user=null;
    				out.write(ActionResult.SUCCESS); 
    			} else if("incomplete".equals(verificationResults)) {
    				out.write("{\"result\":\"incomplete\"}"); 
    			} else if("nonsupport".equals(verificationResults)) {
    				out.write("{\"result\":\"nonsupport\"}"); 
    			}	
    		} else {
    			out.write("{\"result\":\"isnotLong\"}"); 
    		}	
    		out.flush();
    		out.close();

2、在该出进行验证

/**
         * 密码复杂性进行验证 可以包含以下( 0~9,a~z,A~Z,(,),-,.,: )
         * @return
         */
        public String isPwdComplex(String newPwd) {
        	int digit = 0;
        	int lowerString = 0;
        	int upperString = 0;
            int special = 0;
        Boolean flag = true;
    		for(int i = 0; i < newPwd.length(); i++){
    			if(newPwd.charAt(i) >= '0' && newPwd.charAt(i) <= '9') {
    				digit = 1;
    			} else if (newPwd.charAt(i) >= 'a' && newPwd.charAt(i) <= 'z'){
    				lowerString = 1;
    			} else if (newPwd.charAt(i) >= 'A' && newPwd.charAt(i) <= 'Z'){
    				upperString = 1;
    			}else if(newPwd.charAt(i) == '(' || newPwd.charAt(i) == ')' || newPwd.charAt(i) == '-' || newPwd.charAt(i) == '.' || newPwd.charAt(i) == ':') {
    				special = 1;
    			} else {
    				flag = true; // 包含特殊字符，但是不被允许
    			}
    		}
    		if(digit != 1 || lowerString + upperString == 0){
    			return "incomplete";
    		} else if (digit == 1 && lowerString + upperString != 0 && flag == true) {
    			return "correct";
    		} else {
    			return "nonsupport";
    		}
        }

前台返回数据提示

success : function(result) {
    		eval('var obj = '+ result);
    		if (obj.result == "success") {
    			alert("密码修改成功！");
    			window.location.href="";
    		}else if(obj.result == "nonsupport"){
    			alert("某些特殊字符不支持！");
    		}else if(obj.result == "incomplete"){
    			alert("密码必须包含数字和字母！");
    		}else if(obj.result == "isnotLong"){
    			alert("密码至少6位");
    		}else{
    			alert(obj.result);
    		}
        }