Django之文件上传-蒲公英云

Django之文件上传

亦凉 2022-03-11 08:38 295阅读 0赞

一、简单的文件（图片）上传
1、url

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^upload/', views.Upload.as_view()),
]

2、views函数（这里用的CBV）

from django.shortcuts import render, HttpResponse
from django.views import View
class Upload(View):
    def get(self, request):
        return render(request, 'upload.html')
    def post(self, request):
        user = request.POST.get('user')
        img = request.FILES.get('img')
        f = open(img.name, 'wb')
        for line in img.chunks():
            f.write(line)
        f.close()
        return HttpResponse('上传成功')

3、HTML

<form action="/upload/" method="post" enctype="multipart/form-data">
    {% csrf_token %}
    <input type="text" name="user">
    <input type="file" name="img">
    <input type="submit" name="提交">
</form>

二、自定义上传按钮
将“一”中的HTML改为

<form action="/upload/" method="post" enctype="multipart/form-data">
    {% csrf_token %}
    <input type="text" name="user">
    <div style="position: relative">
        <a>上传</a>
        <input type="file" name="img" style="opacity: 0;position: absolute;top: 0;left: 0">
    </div>
    <input type="submit" name="提交">
</form>

三、用Form组件上传
把“一”中的views改为

from django.shortcuts import render, HttpResponse
from django.views import View
from django import forms
from django.forms import fields
class UploadForm(forms.Form):
    user = fields.CharField()
    img = fields.FileField()
class Upload(View):
    def get(self, request):
        return render(request, 'upload.html')
    def post(self, request):
        obj = UploadForm(request.POST, request.FILES)
        if obj.is_valid():
            user = obj.cleaned_data['user']
            img = obj.cleaned_data['img']
            f = open(img.name, 'wb')
            for line in img.chunks():
                f.write(line)
            f.close()
            return HttpResponse('上传成功')