【代码笔记】【c#】两个string[]数组取交集或差集

朱雀 2021-12-19 00:25 308阅读 0赞

/// <summary>
            /// 两个string[]数组 取 交集 或 差集
            /// </summary>
            /// <param name="arr1"></param>
            /// <param name="arr2"></param>
            /// <param name="isIntersected">true取交集 false取差集</param>
            /// <returns></returns>
            public static String[] StringScreen(String[] arr1, String[] arr2, bool isIntersected)
            {
    
                int len = arr1.Length > arr2.Length ? arr1.Length : arr2.Length;
                int o = 0;
    
    
                String[] result = new String[len];
                Dictionary<String, Boolean> map = new Dictionary<String, Boolean>();
    
                foreach (String str1 in arr1)
                {
                    if (!map.ContainsKey(str1))
                    {
                        map[str1] = false;
                    }
                }
    
                foreach (String str2 in arr2)
                {
                    if (str2 != null && !str2.Equals(""))
                    {
                        if (map.ContainsKey(str2))
                        {
                            map[str2] = true;
                        }
                        else
                        {
                            map[str2] = false;
                        }
                    }
                }
    
                foreach (String entry in map.Keys)
                {
                    if (map[entry] == isIntersected)
                    {
                        result[o] = entry;
                        o++;
                    }
                }
    
    
                String[] res = new string[o];
                for (int r = 0; r < o; r++)
                {
                    res[r] = result[r];
                }
    
                return res;
            }