linux/bash:map作为参数传递给function

Love The Way You Lie 2021-11-15 13:01 317阅读 0赞

在linux bash中map是作为数组处理的，不能作为参数直接传递函数，如果一定要传递给函数，要做一些变通处理，示例如下：

#!/bin/bash
    function test_map()
    {
        
    	# 获取map变量的声明字符串
    	# 在本例中为：declare -A user='([name]="tom" [age]="15" [sex]="male" )'
        local var=$(declare -p "$1")
        # 截取=号后的部分: '([name]="tom" [age]="15" [sex]="male" )'
        # 重新创建一个临时map变量ref
        eval "declare -A local ref"=${
        var#*=}
    	
    	# 输出所有的key
        echo keys:${!ref[@]} 
        # 输出所有的value
        echo values:${ref[@]} 
    }
    
    #  定义一个map变量
    declare -A user=(['name']='tom' ['age']='15')
    
    # 再添加一个映射
    user[sex]=male
    
    # 将参数名传递给函数
    test_map user

参考资料：

[https://stackoverflow.com/questions/49901305/how-to-pass-a-map-data-structure-as-an-argument-to-a-method-in-a-bash-script][https_stackoverflow.com_questions_49901305_how-to-pass-a-map-data-structure-as-an-argument-to-a-method-in-a-bash-script]

[https://www.linuxquestions.org/questions/programming-9/bash-passing-associative-arrays-as-arguments-4175474655/][https_www.linuxquestions.org_questions_programming-9_bash-passing-associative-arrays-as-arguments-4175474655]

[https_stackoverflow.com_questions_49901305_how-to-pass-a-map-data-structure-as-an-argument-to-a-method-in-a-bash-script]: https://stackoverflow.com/questions/49901305/how-to-pass-a-map-data-structure-as-an-argument-to-a-method-in-a-bash-script
[https_www.linuxquestions.org_questions_programming-9_bash-passing-associative-arrays-as-arguments-4175474655]: https://www.linuxquestions.org/questions/programming-9/bash-passing-associative-arrays-as-arguments-4175474655/