结构体作为函数参数（值传递，引用传递，指针传递）

淩亂°似流年 2022-05-03 09:30 309阅读 0赞

> 一、值传递  
> \#include <iostream>  
> \#include <string>  
> using namespace std;
> 
> struct Student  
> \{  
>     int id;  
>     string name;  
>     float score\[2\];  
> \};  
> void OutCome(Student s)  
> \{  
>     cout<<s.id<<','<<s.name<<','<<s.score\[0\]<<','<<s.score\[1\]<<endl;  
> \}  
> int main()  
> \{  
>     Student stu=\{2013666,"Tom",\{88,99\}\};  
>     OutCome(stu);  
>     return 0;  
> \}
> 
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> 二、引用传递  
> \#include <iostream>  
> \#include <string>  
> using namespace std;
> 
> struct Student  
> \{  
>     int id;  
>     string name;  
>     float score\[2\];  
> \};  
> //引用传递不会进行内存重新分配，因此和指针传参类似，效率很高  
> void OutCome(Student &s)  //引用传参  
> \{  
>     cout<<s.id<<','<<s.name<<','<<s.score\[0\]<<','<<s.score\[1\]<<endl;  
> \}
> 
> int main()  
> \{  
>     Student stu=\{2013666,"Tom",\{88,99\}\};  
>     OutCome(stu);  
>     return 0;  
> \}
> 
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> 三、指针传递  
> 把结构体的指针作为实参
> 
> \#include <iostream>  
> \#include <string>  
> using namespace std;
> 
> struct Student  
> \{  
>     int id;  
>     string name;  
>     float score\[2\];  
> \};
> 
> void OutCome(Student \*s)  
> \{  
>     //注意指针访问结构体就不能用“.”啦，要用“->”  
>     cout<<s->id<<','<<s->name<<','<<s->score\[0\]<<','<<s->score\[1\]<<endl;  
> \}  
> int main()  
> \{  
>     Student stu=\{2013666,"Tom",\{88,99\}\};  
>     OutCome(&stu);   //这种写法不是特别规范，但可以清晰表明传递的实际上是地址  
>     //嘿嘿，下面这样写才清晰  
>     //Student \*p=&stu;  
>     //OutCome(p)  
>     return 0;  
> \}  
>

转载于：[https://blog.csdn.net/shadowflow/article/details/75006450][https_blog.csdn.net_shadowflow_article_details_75006450]

[https_blog.csdn.net_shadowflow_article_details_75006450]: https://blog.csdn.net/shadowflow/article/details/75006450