日期：根据日期获取星期，查看是否满足日期格式，获取前30N天

朱雀 2021-09-03 04:11 764阅读 0赞

【一】根据日期获取星期

private Integer dateToWeek(String datetime) {
            SimpleDateFormat f = new SimpleDateFormat("yyyy-MM-dd");
            Integer[] weekDays = {7, 1, 2, 3, 4, 5, 6};
            Calendar cal = Calendar.getInstance();
            Date date;
            try {
                date = f.parse(datetime);
                cal.setTime(date);
            } catch (ParseException e) {
                LOGGER.error(HikLog.toLog(ErrorCodes.TIME_PARSE_ERROR.getCode(), ErrorCodes.TIME_PARSE_ERROR.getMessage()));
                e.printStackTrace();
            }
    
            int w = cal.get(Calendar.DAY_OF_WEEK) - 1;
            if (w < 0) {
                w = 0;
            }
            return weekDays[w];
        }

【二】查看是否满足日期格式

private static boolean isTimeLegal(String patternString) {
            Pattern pattern = Pattern.compile("^((\\d{2}(([02468][048])|([13579][26]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])))))|(\\d{2}(([02468][1235679])|([13579][01345789]))[\\-\\/\\s]?((((0?[13578])|(1[02]))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(3[01])))|(((0?[469])|(11))[\\-\\/\\s]?((0?[1-9])|([1-2][0-9])|(30)))|(0?2[\\-\\/\\s]?((0?[1-9])|(1[0-9])|(2[0-8]))))))(\\s((([0-1][0-9])|(2?[0-3]))\\:([0-5]?[0-9])((\\s)|(\\:([0-5]?[0-9])))))?$");
            Matcher result = pattern.matcher(patternString);
            if (result.matches()) {
                return true;
            } else {
                return false;
            }
        }

【三】获取前30N天

private Date getTargetDay(Integer modelPeriod) {
            SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd");
            Date today = new Date();
            String date = fmt.format(today);
            Date minDate = null;
            Calendar calc = Calendar.getInstance();
            try {
                calc.setTime(fmt.parse(date));
    //BusinessConstant.MONTH为30，modelPeriod为周期，BusinessConstant.MONTH * modelPeriod为前30N天
                calc.add(Calendar.DATE, -(BusinessConstant.MONTH * modelPeriod));
                minDate = calc.getTime();
            } catch (ParseException e1) {
                LOGGER.error(HikLog.toLog(ErrorCodes.TIME_PARSE_ERROR.getCode(), ErrorCodes.TIME_PARSE_ERROR.getMessage()));
                e1.printStackTrace();
            }
            return minDate;
        }