C#获取路径

测试账号 2021-01-09 09:38 706阅读 0赞

//获取到bin目录的下层路径：bin\\Debug\\

string aa = System.AppDomain.CurrentDomain.SetupInformation.ApplicationBase;

string cc = System.AppDomain.CurrentDomain.BaseDirectory;

//获取到bin目录：bin\\Debug

string dd = System.Environment.CurrentDirectory;

string ee = System.IO.Directory.GetCurrentDirectory();

string ff = System.Windows.Forms.Application.StartupPath;

//获取程序.exe

string bb = System.Windows.Forms.Application.ExecutablePath;

winform使用相对路径读取文件

目录结构如下图所示：

![20151985712646.png_20150985736][] ![20151985748042.png_2015099745][]

方法一：由于生成的exe文件在bin\\debug目录下，可以使用向上查找目录的方式获取要读取的xml文件

代码如下:

string haarXmlPath = @"../../haarcascade\_frontalface\_alt\_tree.xml";

FileInfo file = new FileInfo(fileName);

string  fullName = file.FullName;

方法二：获取exe文件的路径进行截取，分两次进行，然后拼接文件名，形成全路径

代码如下:

string haarXmlPath = @"haarcascade\_frontalface\_alt\_tree.xml";

string fullName = Application.StartupPath.Substring(0, Application.StartupPath.LastIndexOf("\\\\"));

fullName = fullName.Substring(0, fullName.LastIndexOf("\\\\")) + "\\\\" + haarXmlPath;

另一种方式：

代码如下:

/// <summary>  
/// 获取应用程序根路径  
/// </summary>  
private static string GetApplicationPath()  
\{  
        string path = Application.StartupPath;  
        //string path=AppDomain.CurrentDomain.BaseDirectory; //另一种获取方式  
        string folderName = String.Empty;  
        while (folderName.ToLower() != "bin")  
        \{  
            path = path.Substring(0, path.LastIndexOf("\\\\"));  
            folderName = path.Substring(path.LastIndexOf("\\\\") + 1);  
        \}  
        return path.Substring(0, path.LastIndexOf("\\\\") + 1);  
\}

[20151985712646.png_20150985736]: /images/1610185069790.png
[20151985748042.png_2015099745]: /images/1610185095750.png