android 解决java.lang.SecurityException: Package com.xxx.xxx does not belong to 1000

小咪咪 2024-04-17 06:21 66阅读 0赞

最近遇到一个怪事，访问ContentProvider的call方法一直报这个错，经过不断的研究，终于知道问题在哪了，这里做个记录；

比如，在进程A中调用进程B，进程B再去访问ContentProvider的call、query等方法，而call、query等方法里面又调用了ContentProvider.getCallingPackage()，那么就会报这个错；

先看下ContentProvider.getCallingPackage()的源码，

public final @Nullable String getCallingPackage() {
            final AttributionSource callingAttributionSource = getCallingAttributionSource();
            return (callingAttributionSource != null)
                    ? callingAttributionSource.getPackageName() : null;
        }

public final @Nullable AttributionSource getCallingAttributionSource() {
            final AttributionSource attributionSource = mCallingAttributionSource.get();
            if (attributionSource != null) {
                mTransport.mAppOpsManager.checkPackage(Binder.getCallingUid(),
                        attributionSource.getPackageName());
            }
            return attributionSource;
        }

这里可以看到源码中会拿调用方的包名和uid进行检查，查看是否配对，如果不是，就会抛出异常

/**
         * @deprecated Use {@link PackageManager#getPackageUid} instead
         */
        @Deprecated
        public void checkPackage(int uid, @NonNull String packageName) {
            try {
                if (mService.checkPackage(uid, packageName) != MODE_ALLOWED) {
                    throw new SecurityException(
                            "Package " + packageName + " does not belong to " + uid);
                }
            } catch (RemoteException e) {
                throw e.rethrowFromSystemServer();
            }
        }

问题就出在进程A调用了进程B，进程B去访问ContentProvider.getCallingPackage(), 然后Binder.getCallingUid拿到的是进程A的身份的uid，而不是进程B的身份uid

下面贴下如何解决的？

val token = Binder.clearCallingIdentity()
            val client =
                UMSEnv.applicationContext.contentResolver.acquireUnstableContentProviderClient(
                    providerAuthorityUri
                )
            kotlin.runCatching {
                val extras = Bundle()
                extras.putInt(KEY_HOST_PID, pid)
                val bundle = client?.call(METHOD_QUERY_HOST_PACKAGE_NAME, null, extras)
                client?.close()
                hostPackageName = bundle?.getString(KEY_HOST_PACKAGE_NAME)
            }.onFailure {
                client?.close()
                LogUtils.e(TAG, "queryHostPackageName, exception: $it")
                it.printStackTrace()
            }
            Binder.restoreCallingIdentity(token)

看到上述代码了吗？解决问题的关键方法在于call()前后加上代码

Binder.clearCallingIdentity()

Binder.restoreCallingIdentity(token)

目的就是清除Binder中存储的进程A的身份，这2句代码需要成对使用哦！

下面是相关问题的链接：

[Android ContentProvider调用报错"Bad call: specified package xxx under uid 10032 but it is really 10001"及Binder权限问题分析][Android ContentProvider_Bad call_ specified package xxx under uid 10032 but it is really 10001_Binder]

https://www.jianshu.com/p/a609b965364b

好了又可以愉快玩耍了。

[Android ContentProvider_Bad call_ specified package xxx under uid 10032 but it is really 10001_Binder]: https://www.jianshu.com/p/a609b965364b