HJ68 成绩排序

妖狐艹你老母 2024-03-27 15:18 0阅读 0赞

> [牛客华为机试题库【题号 HJ开头】（重点看）][HJ]  
> [牛客在线编程算法篇【题号NC开头】][NC]  
> [剑指offer【题号 JZ开头】][offer_ JZ]  
> [力扣][Link 1]

### 1）[原题链接][Link 2] ###

### 2）已有题解 ###

### 3）代码 ###

package searchAndOrder;
    
    import java.io.BufferedReader;
    import java.io.IOException;
    import java.io.InputStreamReader;
    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.List;
    import java.util.stream.Collectors;
    
    import static java.lang.Integer.parseInt;
    import static java.lang.System.in;
    
    public class GradeRanking {
        
        public static void main(String[] args) throws IOException {
        
            // 收集数据源
            BufferedReader bf = new BufferedReader(new InputStreamReader(in));
            // 人的信息个数
            int num = parseInt(bf.readLine());
            // 升序还是降序
            int order = parseInt(bf.readLine());
            // 收集人的信息
            List<List<String>> persons = new ArrayList<>();
            for (int i = 0; i < num; i++) {
        
                List<String> person = Arrays.stream(bf.readLine().split(" ")).collect(Collectors.toList());
                persons.add(person);
            }
            bf.close();
    
            // 排序
            List<List<String>> orderPersons = persons.stream().sorted((a, b) -> {
        
                if (order == 0) {
         // 降序
                    return parseInt(b.get(1)) - parseInt(a.get(1));
                } else {
         // 升序
                    return parseInt(a.get(1)) - parseInt(b.get(1));
                }
            }).collect(Collectors.toList());
    
            // 输出
            orderPersons.stream().map(a -> {
        
                return a.stream().collect(Collectors.joining(" "));
            }).forEach(System.out::println);
        }
    }

[HJ]: https://www.nowcoder.com/exam/oj/ta?tpId=37
[NC]: https://www.nowcoder.com/exam/oj
[offer_ JZ]: https://www.nowcoder.com/exam/oj/ta?page=1&tpId=13&type=13
[Link 1]: https://leetcode.cn/problemset/all/
[Link 2]: https://www.nowcoder.com/practice/8e400fd9905747e4acc2aeed7240978b?tpId=37&tqId=21291&rp=1&ru=/exam/oj/ta&qru=/exam/oj/ta&sourceUrl=/exam/oj/ta?page=2&tpId=37&type=37&difficulty=undefined&judgeStatus=undefined&tags=&title=