多线程的创建

柔光的暖阳◎ 2024-03-25 22:10 34阅读 0赞

1.  ### 方式一： ###

继承Thread类

public class Task1 extends Thread{
        @Override
        public void run() {
            PrimeNumber primeNumber = new PrimeNumber();
            for (int i = 2; i <= 100; i++) {
                if (primeNumber.isPrime(i)){
                    System.out.println(i);
                }
            }
        }
    }

### 测试： ###

Task1 task1 = new Task1();
            task1.start();

1.  ### 方式二： ###

实现Runnable接口

public class Task2 implements Runnable{
        @Override
        public void run() {
            LeapYear leapYear = new LeapYear();
            for (int i = 1900; i <= 2023; i++) {
                if (leapYear.isLeap(i)){
                    System.out.println(i);
                }
            }
        }
    }

### 测试： ###

Task2 task2 = new Task2();
            Thread thread = new Thread(task2);
            thread.start();

1.  ### 方式三： ###

实现Callable接口

public class Task3 implements Callable<Boolean> {
        @Override
        public Boolean call() throws Exception {
            LeapYear leapYear = new LeapYear();
            return leapYear.isLeap(2023);
        }
    }

### 测试： ###

Task3 task3 = new Task3();
            FutureTask futureTask = new FutureTask(task3);
            Thread thread = new Thread(futureTask);
            thread.start();
            System.out.println(futureTask.get());

1.  ### 方式四： ###

线程池：

ExecutorService executorService = Executors.newFixedThreadPool(8);
            ThreadPoolExecutor service = (ThreadPoolExecutor) executorService;
            service.setMaximumPoolSize(20);
            service.execute(new Task1());
            service.execute(new Task2());
            try {
                Future future = service.submit(new Task3());
                System.out.println(future.get());
            }catch (Exception e){
                e.printStackTrace();
            }finally {
                service.shutdown();
            }