JAVA抓取网站网页内容

忘是亡心i 2024-02-17 21:06 59阅读 0赞

最近在用JAVA研究下爬网技术,呵呵，入了个门,把自己的心得和大家分享下  
以下提供二种方法，一种是用apache提供的包．另一种是用JAVA自带的.  
代码如下:  
  
  
// 第一种方法  
//这种方法是用apache提供的包,简单方便  
//但是要用到以下包:commons-codec-1.4.jar  
// commons-httpclient-3.1.jar  
// commons-logging-1.0.4.jar  
  
  
public static String createhttpClient(String url, String param) \{  
HttpClient client = new HttpClient();  
String response = null;  
String keyword = null;  
PostMethod postMethod = new PostMethod(url);  
  
  
// try \{  
// if (param != null)  
// keyword = new String(param.getBytes("gb2312"), "ISO-8859-1");  
// \} catch (UnsupportedEncodingException e1) \{  
// // TODO Auto-generated catch block  
// e1.printStackTrace();  
// \}  
  
// NameValuePair\[\] data = \{ new NameValuePair("keyword", keyword) \};  
// // 将表单的值放入postMethod中  
// postMethod.setRequestBody(data);  
// 以上部分是带参数抓取,我自己把它注销了．大家可以把注销消掉研究下  
  
try \{  
int statusCode = client.executeMethod(postMethod);  
response = new String(postMethod.getResponseBodyAsString()  
.getBytes("ISO-8859-1"), "gb2312");//这里要注意下 gb2312要和你抓取网页的编码要一样  
  
String p = response.replaceAll("\\\\&\[a-zA-Z\]\{1,10\};", "")  
.replaceAll("<\[^>\]\*>", "");//去掉网页中带有html语言的标签  
System.out.println(p);  
\} catch (Exception e) \{  
  
e.printStackTrace();  
\}  
return response;  
  
\}  
  
// 第二种方法  
// 这种方法是JAVA自带的URL来抓取网站内容  
  
  
public String getPageContent(String strUrl, String strPostRequest,  
int maxLength) \{  
// 读取结果网页  
StringBuffer buffer = new StringBuffer();  
System.setProperty("sun.net.client.defaultConnectTimeout", "5000");  
System.setProperty("sun.net.client.defaultReadTimeout", "5000");  
try \{  
URL newUrl = new URL(strUrl);  
HttpURLConnection hConnect = (HttpURLConnection) newUrl  
.openConnection();  
// POST方式的额外数据  
if (strPostRequest.length() > 0) \{  
hConnect.setDoOutput(true);  
OutputStreamWriter out = new OutputStreamWriter(hConnect  
.getOutputStream());  
out.write(strPostRequest);  
out.flush();  
out.close();  
\}  
// 读取内容  
  
BufferedReader rd = new BufferedReader(new InputStreamReader(  
hConnect.getInputStream()));  
int ch;  
for (int length = 0; (ch = rd.read()) > -1  
&& (maxLength <= 0 || length < maxLength); length++)  
buffer.append((char) ch);  
String s = buffer.toString();  
s.replaceAll("\\\\&\[a-zA-Z\]\{1,10\};", "").replaceAll("<\[^>\]\*>", "");  
System.out.println(s);  
  
rd.close();  
hConnect.disconnect();  
return buffer.toString().trim();  
\} catch (Exception e) \{  
// return "错误:读取网页失败！";  
//  
return null;  
  
  
\}  
\}  
  
然后写个测试类:  
  
  
public static void main(String\[\] args) \{  
  
String url = "http://www.renren.com";  
String keyword = "人人";  
createhttpClient p = new createhttpClient();  
String response = p.createhttpClient(url, keyword); // 第一种方法  
// p.getPageContent(url, "post", 100500);//第二种方法  
\}  
  
呵呵，看看控制台吧,是不是把网页的内容获取了  
  
第三种方法：  
import java.io.FileOutputStream;  
import java.io.InputStream;  
import java.io.OutputStream;  
import java.net.URL;  
  
  
public class GetUrlToHtml \{  
public static void main(String\[\] args) \{  
InputStream in = null;  
OutputStream out = null;  
  
try \{  
  
  
  
  
if ((args.length != 1)&& (args.length != 2))  
throw new IllegalArgumentException("Wrong number of args");  
  
  
URL url = new URL(args\[0\]);  
in = url.openStream();  
if (args.length == 2)  
out = new FileOutputStream(args\[1\]);  
else out = System.out;  
  
  
  
  
  
  
byte\[\] buffer = new byte\[4096\];  
if(out==System.out)\{new String();\}  
int bytes\_read;  
while((bytes\_read = in.read(buffer)) != -1)\{  
out.write(buffer, 0, bytes\_read);\}  
\}  
  
catch (Exception e) \{  
System.err.println(e);  
System.err.println("Usage: java GetURL <URL> \[<filename>\]");  
\}  
finally \{  
try \{ in.close(); out.close(); \} catch (Exception e) \{\}  
\}  
\}  
\}