华为OD机考真题-解压报文

川长思鸟来 2023-10-13 08:32 4阅读 0赞

/\*\*  
\* 解压报文，输入一个压缩后的报文，返回解压后的原始报文  
\* 压缩规则 n\[str\] 括号内表示压缩的内容 n表示重复次数  
\* 如：3\[m2\[c\]\] 输出mccmccmcc  
\* 10\[k\]2\[mn3\[j2\[op\]\]\]  
\*/

public static void main(String[] args) {
            Stack<Integer> number = new Stack<>();
            Stack<String> str = new Stack<>();
            String value = "3[m2[c]]";
            int index1 = 0;
            StringBuffer sb = new StringBuffer();
            StringBuffer sbTemp1 = new StringBuffer();
            StringBuffer sbTemp2 = new StringBuffer();
    
            StringBuffer sbLoop = new StringBuffer();
            //方法1
            for (int i = 0 ;i < value.length(); i++){
                //入栈
                //方法1.通过正则表达式跟截取值分别入栈
                if (value.charAt(i) == '[' || value.charAt(i) == ']'){
                    String temp = value.substring(index1,i);
                    Pattern pattern = Pattern.compile("\\d+");
                    Matcher matcher = pattern.matcher(temp);
                    while (matcher.find()){
                        number.push(Integer.valueOf(matcher.group()));
                    }
    
                    Pattern pattern1 = Pattern.compile("[a-zA-Z]+");
                    Matcher matcher1 = pattern1.matcher(temp);
                    while (matcher1.find()){
                        str.push(String.valueOf(matcher1.group()));
                    }
                    index1 = i;
                }
    
                //出栈 "10[k]2[mn3[j2[op]]]"
                if (value.charAt(i) == ']') {
                    //从数字栈跟字符串栈中推出值，进行拼接报文
                    while (!str.empty() && !number.empty()) {
                        String temp = str.pop();
                        int size = number.pop();
                        sbTemp2.insert(0,temp);
                        for (int k = 0; k < size; k++) {
                           sbTemp1.append(sbTemp2);
                        }
                        sbTemp2 = sbTemp1;
                        sbTemp1 = new StringBuffer();
                    }
                }
                sb = sb.append(sbTemp2);
                sbTemp1 = new StringBuffer();
                sbTemp2 = new StringBuffer();
            }
     System.out.println("sb:" + sb);
        }
    }