1185. 一周中的第几天

深藏阁楼爱情的钟 2023-10-05 19:41 10阅读 0赞

给你一个日期，请你设计一个算法来判断它是对应一周中的哪一天。

输入为三个整数：`day`、`month` 和 `year`，分别表示日、月、年。

您返回的结果必须是这几个值中的一个 `{"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}`。

**示例 1：**

输入：day = 31, month = 8, year = 2019
    输出："Saturday"

**示例 2：**

输入：day = 18, month = 7, year = 1999
    输出："Sunday"

**示例 3：**

输入：day = 15, month = 8, year = 1993
    输出："Sunday"

**提示：**

*  给出的日期一定是在 `1971` 到 `2100` 年之间的有效日期。

import java.util.Stack;
    import java.text.ParseException;
    import java.text.SimpleDateFormat;
    import java.util.Date;
    
    public class Solution1185 {
    	public String dayOfTheWeek(int day, int month, int year) {
    		String[] d = { "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday" };
    		String mydate = String.valueOf(day) + "/" + String.valueOf(month) + "/" + String.valueOf(year);
    		SimpleDateFormat DateFor = new SimpleDateFormat("dd/MM/yyyy");
    
    		Date date = null;
    		try {
    			date = DateFor.parse(mydate);
    		} catch (ParseException e) {
    
    			e.printStackTrace();
    		}
    
    		String strDateFormat = "u";
    		SimpleDateFormat sdf = new SimpleDateFormat(strDateFormat);
    		int my = Integer.parseInt(sdf.format(date)) - 1;
    
    		return d[my];
    	}
    
    	public static void main(String[] args) {
    
    		Solution1185 s = new Solution1185();
    
    		int day = 31;
    		int month = 8;
    		int year = 2019;
    
    		System.out.println(s.dayOfTheWeek(day, month, year));
    	}
    }