mysql 按天分组

青旅半醒 2023-09-25 09:35 52阅读 0赞

## mysql timestamp类型字段按小时分组 ##

将那列转成字符串，然后截取小时位置，试试可以不SELECT DATE\_FORMAT(createtime,'%Y-%m %H') AS month1,SUM(price) as price1FROM order1GROUP BY month1SELECT SUM(\`amout\`) as \`total\`, SUBSTRING(\`totalprice\`, 12, 2) as \`hours\` FROM \`orders\` WHERE \`createtime\` BETWEEN '2016-09-08 00:00:00' AND '2016-09-08 23:59:59' GROUP BY \`hours\`

![mysql 按天分组\_mysql按天分组][mysql _mysql]

## mysql 分组 从某个时间段按天排序到今天 ##

select\*fromtwheret.datebetween?1and?2orderbyt.date

本回答由提问者推荐

## mySQL分组排序我有一张表，市场份额表，有品牌、品类、市场份额 ##

sock是MySQL监听的Sock文件位置，对于使用RPM安装的用户应该是/var/lib/mysql/mysql。sock，对于使用源码安装则是/tmp/mysql。sock可以根据自己的实际情况进行变更，而pathtochk则是myisamchk所在的位置，DATA\_DIR是你的MySQL数据库存放的位置。

![mysql 按天分组\_mysql按天分组\_02][mysql _mysql_02]

## MySQL的数据类型有哪些呢？ ##

如果用来保存用户的年龄 (举例来说，数据库中保存年龄是不可取的)，用 TINYINT 就够了;九城的《纵横》里，各项技能值，用 SMALLINT 也够了;如果要用作一个肯定不会超过 16000000 行的表的 AUTO\_INCREMENT 的 IDENTIFY 字段，当然用 MEDIUMINT 不用 INT，试想，每行节约一个字节，16000000 行可以节约 10 兆多呢。

## 查询mysql 数据库 如何按年月日分组查询 ##

select

table.year,

table.month,

table.day

(SELECT

year(time) year,

month(time) month,

day(time) day

table) table

group by table.year,table.month,table.day

order BY table.year,table.month,table.day desc;

望采纳,有疑问或是有更好写法,请多交流select \* from 表名 where 时间字段名>=date\_sub(curdate(),interval 7 day);

近一周的数据

select date\_format(d.datetype,'%y%u') as '年份周数',d.shuzhi,d.type

from'date\_dealsheetpage'd

order by d.datetype

select substring(d.datetype, 1,7) as '年份月份',d.shuzhi,d.type

from'date\_dealsheetpage'd

![mysql 按天分组\_mysql按天分组\_03][mysql _mysql_03]

## mysql怎样用时间区间分组 ##

SELECT uptime, CASE WHEN datepart(hour,uptime) IN (0,1) THEN 1

WHEN datepart(hour,uptime) IN (2,3) THEN 2

WHEN datepart(hour,uptime) IN (4,5) THEN 3

WHEN datepart(hour,uptime) IN (6,7) THEN 4

WHEN datepart(hour,uptime) IN (8,9) THEN 5

WHEN datepart(hour,uptime) IN (10,11) THEN 6

WHEN datepart(hour,uptime) IN (12,13) THEN 7

WHEN datepart(hour,uptime) IN (14,15) THEN 8

WHEN datepart(hour,uptime) IN (16,17) THEN 9

WHEN datepart(hour,uptime) IN (18,19) THEN 10

WHEN datepart(hour,uptime) IN (20,21) THEN 11

WHEN datepart(hour,uptime) IN (22,23) THEN 12

ELSE 0 END AS sq

FROM bak\_dircost0901

\-------------------------------

uptime sq

2014/8/19 9:20:59 5

2014/8/22 20:31:20 11

2014/8/22 20:33:08 11

2014/8/26 13:48:01 7

2014/8/27 16:10:45 9select bt.date, s1.cnt, s1.amt, s2.cnt, s2.amt, s3.cnt, s3.amt, s4.cnt, s4.amt from (select date from base\_table group by date) bt

left join (select count(status) cnt, sum(amount) amt, date from base\_table where status = 1 group by status, date) s1

on bt.date = s1.date

left join (select count(status) cnt, sum(amount) amt, date from base\_table where status = 2 group by status, date) s2

on bt.date = s2.date

left join (select count(status) cnt, sum(amount) amt, date from base\_table where status = 3 group by status, date) s3

on bt.date = s3.date

left join (select count(status) cnt, sum(amount) amt, date from base\_table where status = 4 group by status, date) s4

on bt.date = s4.date

[mysql _mysql]: https://img2.baidu.com/it/u=76417558,3824250334&fm=26&fmt=auto
[mysql _mysql_02]: https://img-blog.csdnimg.cn/img_convert/65ffd5f93237b7f6cb970b2a3bf36706.jpeg
[mysql _mysql_03]: https://img1.baidu.com/it/u=2129363902,2237765533&fm=26&fmt=auto