LeetCode（Sorting) 2037. Minimum Number of Moves to Seat Everyone

蔚落 2023-09-23 23:31 49阅读 0赞

# 1.问题 #

There are n seats and n students in a room. You are given an array seats of length n, where seats\[i\] is the position of the ith seat. You are also given the array students of length n, where students\[j\] is the position of the jth student.

You may perform the following move any number of times:

Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)  
Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.

Note that there may be multiple seats or students in the same position at the beginning.

Example 1:

> Input: seats = \[3,1,5\], students = \[2,7,4\]  
> Output: 4  
> Explanation: The students are moved as follows:
> 
>  *  The first student is moved from from position 2 to position 1 using 1 move.
>  *  The second student is moved from from position 7 to position 5 using 2 moves.
>  *  The third student is moved from from position 4 to position 3 using 1 move.  
>     In total, 1 + 2 + 1 = 4 moves were used.

Example 2:

> Input: seats = \[4,1,5,9\], students = \[1,3,2,6\]  
> Output: 7  
> Explanation: The students are moved as follows:
> 
>  *  The first student is not moved.
>  *  The second student is moved from from position 3 to position 4 using 1 move.
>  *  The third student is moved from from position 2 to position 5 using 3 moves.
>  *  The fourth student is moved from from position 6 to position 9 using 3 moves.  
>     In total, 0 + 1 + 3 + 3 = 7 moves were used.

Example 3:

> Input: seats = \[2,2,6,6\], students = \[1,3,2,6\]  
> Output: 4  
> Explanation: Note that there are two seats at position 2 and two seats at position 6.  
> The students are moved as follows:
> 
>  *  The first student is moved from from position 1 to position 2 using 1 move.
>  *  The second student is moved from from position 3 to position 6 using 3 moves.
>  *  The third student is not moved.
>  *  The fourth student is not moved.  
>     In total, 1 + 3 + 0 + 0 = 4 moves were used.

Constraints:

*  n == seats.length == students.length
 *  1 <= n <= 100
 *  1 <= seats\[i\], students\[j\] <= 100

# 2. 解题思路 #

## 方法1： ##

> 1.定义遍历result初始为0，length=seats.length  
> 2.对seats和students进行排序  
> 3.result等于相同索引seats减去student的绝对值  
> 4.返回result

# 3. 代码 #

## 代码1： ##

class Solution {
        
        public int minMovesToSeat(int[] seats, int[] students) {
        
            int result =0;
            int length = seats.length;//1.定义遍历result初始为0，length=seats.length
            Arrays.sort(seats);//2.对seats和students进行排序
            Arrays.sort(students);
            for (int i = 0; i < length; i++) {
        //3.result等于相同索引seats减去student的绝对值
                result+= Math.abs(seats[i]-students[i]);
            }
            return result;//4.返回result
            
        }
    }

解题思路和上面基本相同

class Solution {
        
        public int minMovesToSeat(int[] seats, int[] students) {
        
            int result =0;
            int length = seats.length;
            Arrays.sort(seats);
            Arrays.sort(students);
            for(int i = 0;i<seats.length;i++){
        
    	        if(seats[i] >= students[i]){
        
    	            sum = sum + (seats[i] - students[i]);
    	        }
    	        
    	        else if(seats[i] < students[i]){
        
    	            sum = sum + (students[i] - seats[i]);
    	        }
        	}
            return result;
            
        }
    }