java 将字符串转为对象，对应到实体类//转成map(亲测)

待我称王封你为后i 2023-09-23 15:13 91阅读 0赞

来源：[java 将字符串转为对象，对应到实体类//转成map\_murongyuyao的博客-CSDN博客\_java 字符串转对象][java _map_murongyuyao_-CSDN_java]

maven

<dependency>
    	    <groupId>com.alibaba</groupId>
    	    <artifactId>fastjson</artifactId>
    	    <version>1.2.62</version>
    	</dependency>

主方法

package test;
    
    import com.alibaba.fastjson.JSON;
    import com.alibaba.fastjson.JSONObject;
    
    public class test1 {
        public static void main(String[] args){
            String str = "{\"id\":\"1\",\"name\":\"吴彦祖\",\"age\":\"46\"}";
            //将字符串转为json数据
            JSONObject json = JSONObject.parseObject(str);
            System.out.println(json.toJSONString());
            //json数据按key取值
            System.out.println(json.getString("name"));
            System.out.println(json.getString("age"));
            //将json数据转换为java对象/实体类
            UserBean user = JSON.parseObject(str, UserBean.class);
            System.out.println(user.toString());
            //将字符串转成map集合
            Map<String, String> maps = JSON.parseObject(hashMap, HashMap.class);
            System.out.println(maps)
            //将java对象/实体类转换为json数据
            JSONObject jsonUser = (JSONObject) JSONObject.toJSON(user);
            System.out.println("jsonUser："+jsonUser);
        }
    }

实体类：

package test;
    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    public class UserBean {
        private String name;
        private String id;
        private String age;
    
    }

json合并

import com.alibaba.fastjson.JSONObject;
    
    public class test1 {
        public static void main(String[] args){
            JSONObject json1 = new JSONObject();
            JSONObject json2 = new JSONObject();
    
            json1.put("name", "吴彦祖");
            json1.put("age", "46");
            System.out.println(json1.toString());
    
            json2.put("address", "香港");
            json2.put("profession", "演员");
            System.out.println(json2.toString());
    
            JSONObject jsonMerge = new JSONObject();
    
            jsonMerge.putAll(json1);
            jsonMerge.putAll(json2);
    
            System.out.println("合并后："+jsonMerge.toString());
    
        }
    }

[java _map_murongyuyao_-CSDN_java]: https://blog.csdn.net/murongyuyao/article/details/123891919