C语言-十进制/二进制数的互相转化-蒲公英云

C语言-十进制/二进制数的互相转化

一、编写一个程序，将输入的十进制数转化为二进制表示。例如：输入十进制数64，输出二进制数表示1000000

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void deTobi(int a) {
    int i = 0, stack[10], r, s;
    do {
        r        = a / 2;
        s        = a % 2;
        stack[i] = s;
        if (r != 0) {
            ++i;
            a = r;
        }
    } while (r);
    for (; i >= 0; --i) {
        printf("%d", stack[i]);
    }
    printf("\n");
}
int main(int argc, const char *argv[]) {
    int a;
    printf("Please input aDecimal digit less than 1023\n");
    scanf("%d", &a);
    deTobi(a);
    return 0;
}

调试运行：

如果只是单纯打印我们可以利用递归巧妙的打印出某数的二进制，代码很精简

void binary(int n) {
    if (n / 2) {
        binary(n / 2);
    }
    printf("%d", n % 2);
}

二、递归实现二进制转化为十进制

#include "math.h"
void biTode2(int n,int *sum,int *m){
    char c;
    scanf("%c",&c);
    if (c!='#') {
        *m = *m+1;
        biTode2(n+1, &(*sum), &(*m));
    }
    if(c=='1') *sum=*sum+pow(2, (*m)-n-1);
}
int main(int argc, const char *argv[]) {
    int sum = 0,m = 0;
    printf("Please input a binary number ending for '#'\n");
    biTode2(0, &sum, &m);
    printf("The Decimal Decimal digit is \n");
    printf("%d ",sum);
    return 0;
}