链表LinkedList实现栈(Java)
链表LinkedList实现栈
LinkedList.java(链表)详细请看链表LinkedList(Java)
public class LinkedList<E> {
private class Node {
// 内部类将节点设为私有 隐藏实现细节
public E e;// 元素
public Node next;// next指针
public Node(E e, Node next) {
this.e = e;
this.next = next;
}
public Node(E e) {
this(e, null);
}
public Node() {
this(null, null);
}
@Override
public String toString() {
return e.toString();
}
}
private Node dummyhead; // 设置虚拟头节点
int size;// 链表中元素个数
public LinkedList() {
// TODO Auto-generated constructor stub
dummyhead = new Node(null, null);
size = 0;
}
// 获取链表中的元素个数
public int getSize() {
return size;
}
// 返回链表是否为空
public boolean isEmpty() {
// TODO Auto-generated method stub
return size == 0;
}
// 在链表的index位置添加一个元素
public void add(int index, E e) {
if (index < 0 || index > size) {
try {
throw new Exception("index越界");
} catch (Exception e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
Node prev = dummyhead;// 创建一个索引与dummyhead指向一致
for (int i = 0; i < index; i++) // 需要找到索引的前一个位置
prev = prev.next;// prev在链表中移动
// Node node = new Node(e);//创建一个node
// node.next = prev.next;//node.next指向prev.next
// prev.next = node;//prev.next指向node
prev.next = new Node(e, prev.next);// 等于 上面3行代码
size++;
}
// 在链表尾部添加元素
public void addLast(E e) {
add(size, e);
}
// 在链表头添加元素
public void addFirst(E e) {
// TODO Auto-generated method stub
add(0, e);
}
// 获得链表的第index个元素
public E get(int index) {
if (index < 0 || index > size) {
try {
throw new Exception("index越界");
} catch (Exception e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
Node cur = dummyhead.next;// 寻找第index个元素
for (int i = 0; i < index; i++)
cur = cur.next;
return cur.e;// 返回cur.e就是第index个元素
}
// 获得第一个元素
public E getFirst() {
return get(0);
}
// 获得最后一个元素
public E getLast() {
return get(size - 1);
}
// 修改链表的第index个元素
public void set(int index, E e) {
if (index < 0 || index >= size) {
try {
throw new Exception("index越界");
} catch (Exception e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
}
Node cur = dummyhead.next;// 寻找第index个元素
for (int i = 0; i < index; i++)
cur.e = e;
}
// 查找链表中是否有元素e
public boolean contains(E e) {
Node cur = dummyhead.next;
while (cur != null) {
if (cur.e.equals(e)) // 判断cur.e是否等于用户传来的e
return true;
cur = cur.next;// 依次遍历
}
return false;
}
public String toString() {
StringBuilder res = new StringBuilder();
// Node cur = dummyhead.next;
// while (cur != null) {
// res.append(cur + "->");
// cur = cur.next;
// }
for (Node cur = dummyhead.next; cur != null; cur = cur.next)
res.append(cur + "->");
res.append("NULL");
return res.toString();
}
// 删除链表中第index个元素,并返回删除的元素
public E remove(int index) {
if (index < 0 || index > size) {
try {
throw new Exception("index越界");
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Node prev = dummyhead;
for (int i = 0; i < index; i++)
prev = prev.next;
Node retNode = prev.next;// prev.next与retNode所指的都是要删除的节点
prev.next = retNode.next;// prev.next跳过retNode直接指向retNode.next
retNode.next = null;// 垃圾回收retNode.next
size--;
return retNode.e;
}
// 删除链表中第一个元素,返回删除的元素
public E removeFirst() {
return remove(0);
}
// 删除链表中最后一个元素,返回删除的元素
public E removeLast() {
return remove(size - 1);
}
}
Stack.java(栈接口)
public interface Stack<E> {
int getSize();//获取栈中元素个数
boolean isEmpty();//判断栈是否为空
void push(E e);//入栈
E pop();//获取栈顶元素并且出栈
E peek();//查看栈顶元素
}
LinkedListStack.java(链表实现的栈)
public class LinkedListStack<E> implements Stack<E>{
private LinkedList<E> list;
public LinkedListStack() {
// TODO Auto-generated constructor stub
list = new LinkedList<>();
}
@Override
public int getSize() {
// TODO Auto-generated method stub
return list.getSize();
}
@Override
public boolean isEmpty() {
// TODO Auto-generated method stub
return list.isEmpty();
}
@Override
public void push(E e) {
// TODO Auto-generated method stub
list.addFirst(e);
}
@Override
public E pop() {
// TODO Auto-generated method stub
return list.removeFirst();
}
@Override
public E peek() {
// TODO Auto-generated method stub
return list.getFirst();
}
public String toString() {
StringBuilder res = new StringBuilder();
res.append("Stack:top ");
res.append(list);
return res.toString();
}
}
测试(main)
public class StackTest {
public static void main(String[] args) {
LinkedListStack<Integer> stack = new LinkedListStack<>();
for (int i = 0; i < 5; i++) {
stack.push(i);
System.out.println(stack);
}
stack.pop();
System.out.println(stack);
}
}
测试结果
链表实现的栈的时间复杂度
入栈:O(1)
出栈:O(1)
查询栈顶元素:O(1)
链表栈需要不停的重新new Node,需要在内存中开发内存,如果操作越多,耗时会越长
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