SpringBoot从零搭建一个项目(五)定义返回格式
如果我们直接返回对象的json格式,对于客户端来说,使用体验不是很好,一般还要返回code和错误信息,所以这里我们做一次封装。
先定义返回的格式如下:
{
data: {}
code: 100
msg:“正常”
}
封装返回的类:
public class JsonResult {
public static String CODE_SUCCESS = "100";
public static String CODE_FAIL = "101";
private Object data;
private String code;
private String msg;
public JsonResult(Object data, String code, String msg) {
this.data = data;
this.code = code;
this.msg = msg;
}
/**
* 成功
* @param data
* @return
*/
public static JsonResult buildData(Object data) {
return new JsonResult(data, CODE_SUCCESS, "");
}
/**
* 失败
* @return
*/
public static JsonResult buildFail() {
return new JsonResult("", CODE_FAIL, "异常");
}
}
定义一个控制层基础类,方便在控制层中直接返回格式
public class BaseController {
/**
* 成功-带参数
* @param t
* @return
*/
public String success(Object t) {
JsonResult jsonResult = JsonResult.buildData(t);
String resultString = JSONObject.fromObject(jsonResult).toString();
return resultString;
}
/**
* 失败-通用
* @return
*/
public String fail() {
JsonResult jsonResult = JsonResult.buildFail();
String resultString = JSONObject.fromObject(jsonResult).toString();
return resultString;
}
}
在控制层中使用:
@RestController
@RequestMapping("/user")
public class UserController extends BaseController {
@RequestMapping("/login")
public String registerAndLogin(
@RequestParam("code") String code,
@RequestParam("nickName") String nickName,
@RequestParam("avatarUrl") String avatarUrl) {
// .......
return success(user);
}
}
返回的结果:
{
code: "100"
data: {avatarUrl: "https://wx.qlogo.cn/mmopen/vi_32/DYAIOgq83eo4kicic…MvuIu6doOsvxelA87fzvuAL5rnx3JwCDRXice2HtnzUwQ/132", createDate: "2020-08-04 16:10:40.0", nickName: "WongWoo", openid: "oW_rF5DQwwRl7Ek2ApqrXJryYVMM", unionid: "", …}
msg: ""
}
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