输入日期计算这个日期在这一年里是多少天成功返回天数不成功返回-1（c++）

超、凢脫俗 2023-02-18 08:30 3阅读 0赞

#include<iostream>
    using namespace std;
    int count(int year,int month, int day)
    {
    	int days = 0;
    	if (month < 13 && day <= 31)
    	{
    
    		switch (month)
    		{
    		case 1:	
    			days = day;
    			break;
    		case 2:
    			days = 31 + day;
    			if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    			{
    				if (day > 29)
    				{
    					days = 0;
    				}
    			}
    			else
    			{
    				if (day > 28)
    				{
    					days = 0;
    				}
    			}
    			break;
    		case 3:
    			days = 31 + day + 29;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		case 4:
    			days = 31 * 2 + day + 29;
    			if (day > 30)
    			{
    				days = 0;
    			}
    			break;
    		case 5:
    			days = 31 * 2 + day + 29 + 30;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		case 6:
    			days = 31 * 3 + day + 29 + 30;
    			if (day > 30)
    			{
    				days = 0;
    			}
    			break;
    		case 7:
    			days = 31 * 3 + day + 29 + 30 * 2;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		case 8:
    			days = 31 * 4 + day + 29 + 30 * 2;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		case 9:
    			days = 31 * 5 + day + 29 + 30 * 2;
    			if (day > 30)
    			{
    				days = 0;
    			}
    			break;
    		case 10:
    			days = 31 * 5 + day + 29 + 30 * 3;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		case 11:
    			days = 31 * 6 + day + 29 + 30 * 3;
    			if (day > 30)
    			{
    				days = 0;
    			}
    			break;
    		case 12:
    			days = 31 * 6 + day + 29 + 30 * 4;
    			if (day > 31)
    			{
    				days = 0;
    			}
    			break;
    		default:
    			break;
    		}
    	}
    	else
    	{
    		days = 0;
    	}
    	return days;
    }
    int main()
    {
    	int days;
    	int year, month, day;
    	while (cin >> year >> month >> day)
    	{
    		days = count(year,month, day);
    		if (days == 0)
    		{
    			cout << -1 << endl;
    		}
    		else
    		{
    			if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    			{
    
    				cout << days << endl;
    			}
    			else
    			{
    				cout << days - 1 << endl;
    
    			}
    		}
    	}
    }