Java快速调用Python代码

小鱼儿 2023-02-13 08:48 6阅读 0赞

**1.配置pom.xml**

>   
> <dependency>  
>     <groupId>org.python</groupId>  
>     <artifactId>jython</artifactId>  
>     <version>2.7.0</version>  
> </dependency>

**2.环境异常则搭建：Run/Debug Configurations运行环境配置**

<table style="width:500px;"> 
 <tbody> 
  <tr> 
   <td> <p><strong>Environment variables</strong></p> </td> 
  </tr> 
 </tbody> 
</table>

<table style="width:500px;"> 
 <tbody> 
  <tr> 
   <td>PATH <p>&nbsp;</p> </td> 
   <td>C:/ProgramData/Anaconda3</td> 
  </tr> 
 </tbody> 
</table>

**3.代码编写**

①直接写代码

public void test2() {
            //解决报错Cannot import site module and its dependencies: No module named site
            Properties props = new Properties();
            props.put("python.home", "path to the Lib folder");
            props.put("python.console.encoding", "UTF-8");
            props.put("python.security.respectJavaAccessibility", "false");
            props.put("python.import.site", "false");
            Properties preprops = System.getProperties();
            PythonInterpreter.initialize(preprops, props, new String[0]);
            PythonInterpreter interpreter = new PythonInterpreter();
            interpreter.exec("num=[13,7,2,9,14,7,6]; ");
            interpreter.exec("print(sorted(num));");
        }

②调用外部代码，可传参

public void test1() {
            String a = "1";
            String b = "2";
            Process proc = null;
            BufferedReader in = null;
            try {
                String pyRec = this.getClass().getResource("/python/pytest1.py").getPath().substring(1);
                System.out.println(pyRec);
                String[] args = new String[]{"python", pyRec, a, b};
                proc = Runtime.getRuntime().exec(args);
                in = new BufferedReader(new InputStreamReader(proc.getInputStream()));
                proc.waitFor();
                String line = null;
                while ((line = in.readLine()) != null) {
                    System.out.println(line);
                }
            } catch (IOException | InterruptedException e) {
                e.printStackTrace();
            }finally {
                if (null != in) {
                    try {
                        in.close();
                    } catch (IOException e) {
                        e.printStackTrace();
                    }
                }
            }
        }
    }