多线程练习-熊吃蜂蜜

阳光穿透心脏的1/2处 2023-01-20 09:45 172阅读 0赞

## 要求 ##

现在有一个罐子，两只熊，十只蜜蜂，每只蜜蜂每隔十秒产生一滴蜂蜜，熊大一次吃5滴蜂蜜，熊二一次吃10滴蜂蜜，吃完就不吃了。

## 实现 ##

罐子的实现

static class Contanier {
            private int honey;
    
            public Contanier() {
    
            }
    
            public void add() {
                synchronized (Contanier.class) {
                    honey += 1;
                }
            }
    
            public Boolean eat(int appetite) {
                synchronized (Contanier.class) {
                    if (honey / appetite > 0) {
                        honey -= appetite;
                        return true;
                    } else {
                        return false;
                    }
                }
            }
        }

熊

static class Bear implements Runnable {
    
            private int appetite;
    
            private Contanier contanier;
    
            Boolean eated = false;
    
            public Bear(Contanier contanier, int appetite) {
                this.contanier = contanier;
                this.appetite = appetite;
            }
    
            @Override
            public void run() {
                while (!eated) {
                    eated = contanier.eat(appetite);
                    if (eated) {
                        System.out.println("熊" + Thread.currentThread().getName() + "吃到蜂蜜了，终止线程");
                    }
                }
            }
        }

小蜜蜂

static class Bee implements Runnable {
            private Contanier contanier;
    
            public Bee(Contanier contanier) {
                this.contanier = contanier;
            }
    
            @Override
            public void run() {
                while (true){
                    try {
                        Thread.sleep(10000);
                        contanier.add();
                        System.out.println("小蜜蜂"+Thread.currentThread().getName() +"生产了蜂蜜");
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        }

执行方法

public static void main(String[] args) {
           Contanier contanier = new Contanier();
           for (int i= 0; i< 10; i++){
               Thread thread = new Thread(new Bee(contanier), ""+i);
               thread.start();
           }
            Thread bear1 = new Thread(new Bear(contanier,5), "大");
            bear1.start();
            Thread bear2 = new Thread(new Bear(contanier, 10), "二");
            bear2.start();
        }

### 运行效果 ###

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