Java一个小练习----String类型转换int类型
Java一个小练习
把字符串str分割程String数组,然后转换成int数组,排序
String str = "123 345 89 93 2 6573 223"
然后在拼接成一个字符串如下:
"2 89 93 123 223 345 6573"
/**
* String str = "123 345 89 93 2 6573 223"
* 把字符串str分割程String数组,然后转换成int数组,排序
* 然后在拼接成一个字符串如下:
* "2 89 93 123 223 345 6573"
*/
public class StringToInt {
public static void main(String[] args) {
String str = "123 345 89 93 2 6573 223";
//输出原字符串
System.out.println("str1 = "+str);
//分割字符串给赋给arr数组
String[] arr = str.split(" ");
//输出arr数组
System.out.print("arr = ");
for (int i = 0; i < arr.length; i++) {
System.out.print(arr[i]+"\t");
}
System.out.println();
int []arrInt = new int[str.length()];
//String转int
for (int i = 0; i < arr.length; i++) {
arrInt[i] = Integer.parseInt(arr[i]);
}
//遍历int数组
System.out.print("arrInt = ");
for (int i = 0; i < arr.length; i++) {
System.out.print(arrInt[i]+"\t");
}
System.out.println();
//排序
for (int i = 0; i < arr.length-1; i++) {
for (int j = 0; j < arr.length-1-i; j++) {
int arr1;
if (arrInt[j]>arrInt[j+1]){
arr1 = arrInt[j];
arrInt[j] = arrInt[j+1];
arrInt[j+1] = arr1;
}
}
}
System.out.print("排好序的新数组 = ");
for (int i = 0; i < arr.length; i++) {
System.out.print(arrInt[i]+"\t");
}
System.out.println();
//int数组转换String
StringBuffer sb = new StringBuffer();
for (int i = 0; i < arr.length; i++) {
sb.append(arrInt[i]+" ");
}
System.out.print("sb = "+sb);
}
}
运行结果如下:
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