golang最简单的server和client

本是古典何须时尚 2022-12-20 14:54 182阅读 0赞

client端

package main
    import (
    	"bytes"
    	"fmt"
    	"io/ioutil"
    	"net/http"
    	"net/url"
    )
    func main() {
    	request_url := "http://localhost:8080/"
    	// 要 POST的 参数
    	form := url.Values{
    		"name": {"xiaoming"},
    		"address":  {"beijing"},
    		"subject":  {"Hello"},
    		"from":     {"china"},
    	}
    	// func Post(url string, bodyType string, body io.Reader) (resp *Response, err error) {
    	//对form进行编码
    	body := bytes.NewBufferString(form.Encode())
    	rsp, err := http.Post(request_url, "application/x-www-form-urlencoded", body)
    	if err != nil {
    		panic(err)
    	}
    	defer rsp.Body.Close()
    	body_byte, err := ioutil.ReadAll(rsp.Body)
    	if err != nil {
    		panic(err)
    	}
    	fmt.Println(string(body_byte))
    }

server端

package main
    
    import (
        "fmt"
        "log"
        "net/http"
    )
    
    func main() {
        http.HandleFunc("/", ExampleHandler)
        if err := http.ListenAndServe(":8080", nil); err != nil {
            log.Fatal(err)
        }
    }
    
    func ExampleHandler(w http.ResponseWriter, r *http.Request) {
    
        // Double check it's a post request being made
        if r.Method != http.MethodPost {
            w.WriteHeader(http.StatusMethodNotAllowed)
            fmt.Fprintf(w, "invalid_http_method")
            return
        }
    
        // Must call ParseForm() before working with data
        r.ParseForm()
    
        // Log all data. Form is a map[]
        log.Println(r.Form)
    
        // Print the data back. We can use Form.Get() or Form["name"][0]
        fmt.Fprintf(w, "Hello "+r.Form.Get("name"))
    }
    
    
    //可以直接命令行请求
    
    //curl -X POST http://localhost:8080 -d "name=zhangsan"