maven assembly打包zip报错 You must set at least one file.

Dear 丶 2022-12-20 12:41 244阅读 0赞

### 文章目录 ###

*   *  maven assembly打包Error creating assembly archive pack: You must set at least one file.

## maven assembly打包Error creating assembly archive pack: You must set at least one file. ##

问题背景：  
今天maven 使用assembly插件打包spring boot项目到zip 报错  
Error creating assembly archive pack: You must set at least one file.

pom插件配置如下:

<plugin>
                    <artifactId>maven-assembly-plugin</artifactId>
                    <executions>
                        <execution>
                            <phase>package</phase>
                            <goals>
                                <goal>single</goal>
                            </goals>
                            <configuration>
                                <finalName>${ project.artifactId}-${ project.version}-${ maven.build.timestamp}</finalName>
                                <appendAssemblyId>false</appendAssemblyId>
                                <descriptors>
                                    <descriptor>src/assembly/assembly-descriptor.xml</descriptor>
                                </descriptors>
                            </configuration>
                        </execution>
                    </executions>
                </plugin>

assembly文件如下：

<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3 http://maven.apache.org/xsd/assembly-1.1.3.xsd">
    	<id>zip-assembly</id>
    	<formats>
    		<format>zip</format>
    	</formats>
    	<includeBaseDirectory>false</includeBaseDirectory>
    	<fileSets>
    		
    		<fileSet>
    			<directory>src/main/scripts</directory>
    			<outputDirectory>scripts</outputDirectory>
    			<includes>
    				<include>*.sh</include>
    			</includes>
    			<fileMode>0755</fileMode>
    			<lineEnding>unix</lineEnding>
    		</fileSet>
    		<fileSet>
    			<directory>src/main/config</directory>
    			<outputDirectory>config</outputDirectory>
    			<includes>
    				<include>app.properties</include>
    			</includes>
    			<lineEnding>unix</lineEnding>
    		</fileSet>
    		<fileSet>
    			<directory>src/main/config</directory>
    			<outputDirectory>/</outputDirectory>
    			<includes>
    				<include>apollo-portal.conf</include>
    			</includes>
    			<lineEnding>unix</lineEnding>
    		</fileSet>
    		<fileSet>
    			<directory>target/classes</directory>
    			<outputDirectory>/config</outputDirectory>
    			<includes>
    				<include>application-github.properties</include>
    				<include>apollo-env.properties</include>
    			</includes>
    		</fileSet>
    		
    		<fileSet>
    			<directory>target</directory>
    			<outputDirectory>/</outputDirectory>
    			<includes>
    				<include>${project.artifactId}-*.jar</include>
    			</includes>
    			<fileMode>0755</fileMode>
    		</fileSet>
    	</fileSets>
    </assembly>

问题分析：  
经过测试，发现报这个错，本质是因为你assembly配置的 fileSet中的文件一个都找不到，它没有东西能帮你打包成zip。

解决方案：  
检查自己的写文件路径对不对。

我这里的原因是，pom.xml 中多了个 finalName, 生成jar命名就成了xxx.jar，我assembly配置的 fileSet的$\{project.artifactId\}-\*.jar匹配不上，导致无文件可打成zip，因而报错！