【JAVA】【华为校园招聘笔试-软件】2020-09-09

╰+哭是因爲堅強的太久メ 2022-12-05 10:18 107阅读 0赞

# 前言 #

华为三道题，100+200+300，100及格，大家做对第一题就好了，祝大家全都有心仪的offer，不要慌，不要焦虑  
![在这里插入图片描述][2020090920535724.png_pic_center]

# 一、完美排列——玩具（全A）（注意：题目中说：如果不是完美排列，则输出0，没注意这种情况的应该A0.6或0.7） #

## 代码：暴力就完事了 ##

package huawei0909;
    
    import java.util.Scanner;
    
    /** * Created by IntelliJ IDEA. * * @Author: * @Email: * @Date: 2020/9/9 * @Time: 19:04 * @Version: 1.0 * @Description: Description */
    public class First { 
        public static void main(String[] args) { 
            Scanner sc = new Scanner(System.in);
            int K = sc.nextInt();
            int[] perArr = new int[K];
            int[] perArr1 = new int[K];
            for (int i = 0; i < K; i++)
                perArr[i] = sc.nextInt();
            for (int i = 0; i < K; i++)
                perArr1[i] = sc.nextInt();
            int n = sc.nextInt();
            int[] arr = new int[n];
            int[] arr1 = new int[n];
            for (int i = 0; i < n; i++)
                arr[i] = sc.nextInt();
            for (int i = 0; i < n; i++)
                arr1[i] = sc.nextInt();
            sc.close();
            /*if (n<K){ //必须判断，不然A0.6或0.7，因为题目中说：如果不是完美排列，则输出0，详情看下面的System.out.println(i + 1); System.out.println(0); return; }*/
            for (int i = 0; i < n; i++) { 
                if (arr[i] == perArr[0] && arr1[i] == perArr1[0] && i + K - 1 < n && arr[i + K - 1] == perArr[K - 1] && arr1[i + K - 1] == perArr1[K - 1]) { 
                    boolean flag = true;
                    int index = i;
                    for (int j = 1; j < K - 1; j++) { 
                        index++;
                        if (!(arr[index] == perArr[j] && arr1[index] == perArr1[j])) { 
                            flag = false;
                            break;
                        }
                    }
                    if (flag) {  //输出可能为0，如果没考虑到，则A0.6或0.7，因为题目中说：如果不是完美排列，则输出0
                        System.out.println(i + 1);
                        return;
                    }
                }
            }
            System.out.println(0); //必须有，不然A0.6或0.7，因为题目中说：如果不是完美排列，则输出0，详情看下面的System.out.println(i + 1);
        }
    }

# 二、最长的水沟（全A） #

package huawei0909;
    
    import java.util.Scanner;
    
    /** * Created by IntelliJ IDEA. * * @Author: * @Email: * @Date: 2020/9/9 * @Time: 19:36 * @Version: 1.0 * @Description: Description */
    public class Second { 
        public static int[][] matrix;
        public static int[][] dp;
        public static int[][] k = { { 1, 0}, { 0, 1}, { -1, 0}, { 0, -1}};
        public static int n, m, ans;
    
        public static void main(String[] args) { 
            Scanner sc = new Scanner(System.in);
            n = sc.nextInt();
            m = sc.nextInt();
            matrix = new int[n + 1][m + 1];
            dp = new int[n + 1][m + 1];
            for (int i = 1; i <= n; i++)
                for (int j = 1; j <= m; j++)
                    matrix[i][j] = sc.nextInt();
            for (int i = 1; i <= n; i++)
                for (int j = 1; j <= m; j++)
                    ans = Math.max(ans, dfs(i, j));
            System.out.println(ans + 1);
        }
    
        public static int dfs(int x, int y) { 
            if (dp[x][y] != 0)
                return dp[x][y];
            for (int i = 0; i <= 3; i++) { 
                int tx = x + k[i][0];
                int ty = y + k[i][1];
                if (!(tx < 1 || ty < 1 || tx > n || ty > m || matrix[tx][ty] >= matrix[x][y]))
                    dp[x][y] = Math.max(dp[x][y], 1 + dfs(tx, ty));
            }
            return dp[x][y];
        }
    }

# 三、最大异或路径（A3.33） #

[2020090920535724.png_pic_center]: /images/20221123/d0ddf1650382401592c8f8ebd374e0ec.png