scala编写：用户登录账号密码的程序，只有3次机会

你的名字 2022-11-20 11:54 167阅读 0赞

import scala.io.StdIn
    import scala.util.control.Breaks._
    object denglu {
        
      def main(args:Array[String]):Unit = {
        
        val usr_name = "itcast"
        val usr_password = "heima"
        breakable{
        
          for(i <- 1 to 3){
        
            println("请输入你的账号：")
            val name = StdIn.readLine()
            println("请输入你的密码：")
            val password = StdIn.readLine()
            if (name == usr_name && password == usr_password){
        
              println("登陆成功，开始学习Scala！")
              break()
            }else{
        
              println(s"用户名或者密码错误，您还有${3-i}次机会")
            }
          }
          println("您的账号已被锁定，请联系管理员亲(づ￣3￣)づ╭❤～")
        }
    
      }
    }

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[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70_pic_center 1]: /images/20221120/5b94500d90d947d28715424dc90ba3bb.png