Java学习之计算矩阵A+B 、矩阵A-B和矩阵A的转置矩阵案例

矫情吗；* 2022-11-15 14:23 120阅读 0赞

**案例详情：**

已知两个3x4矩阵A和B，计算A+B 、A-B和A的转置矩阵。

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NzA2MjkwNw_size_16_color_FFFFFF_t_70_pic_center]

**案例代码：**

public class MatrixDemo {
        
    	public static void printArray(int [][] array){
        
    		for(int i = 0; i < array.length; i++){
        
    			for(int j = 0; j < array[i].length; j++){
        
    				System.out.print(array[i][j] +" ");
    			}
    			System.out.println();
    		}
    	System.out.println();
    	}
    
    	public static void main(String args[]){
        
    		int[][] a = {
        {
        1,3,5},{
        -3,6,0},{
        13,-5,7},{
        -2,19,25}};
    		int[][] b = {
        {
        0,-1,-2},{
        7,-1,6},{
        -6,13,2},{
        12,- 8,-13}};
    		int[][] sum = new int[4][3];
    		int[][] minus = new int[4][3];
    		int[][] transpose = new int[a[0].length][a.length];
    		for(int i = 0; i < a.length; i++){
        
    			for(int j = 0; j < a[i].length; j++){
        
    				sum[i][j] = a[i][j] + b[i][j];
    				minus[i][j] = a[i][j] - b[i][j];
    			}
    		}
    		//求a的转置
    		for(int i = 0; i < transpose.length; i++){
        
    			for(int j = 0; j < transpose[0].length; j++){
        
    				transpose[i][j] = a[j][i];
    			}
    		}
    		System.out.println("(1)矩阵a+矩阵b = ");
    		printArray(sum);
    		System.out.println("(2)矩阵a-矩阵b = ");
    		printArray(minus);
    		System.out.println("(3)矩阵a的转置 = ");
    		printArray(transpose);
    	}
    }

**案例运行图：**

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NzA2MjkwNw_size_16_color_FFFFFF_t_70_pic_center 1]

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[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NzA2MjkwNw_size_16_color_FFFFFF_t_70_pic_center 1]: /images/20221022/0c558e5dd8c44c4e9ef245956b838b4b.png