分别使用for()、while()和do while()循环实现n(1≤n≤100)个数的累加求和

叁歲伎倆 2022-11-12 08:22 213阅读 0赞

#include<stdio.h>
    int f1(short n)//使用while()循环
    {
        int Sum=0;
        int m;
        short i=1;
        while(i<=n)
        {
            scanf("%d", &m);
            Sum=Sum+m;
            i++;
        }
        return Sum;
    }
    int f2(short n)//使用for()循环
    {
        int Sum=0;
        int m;
        short i;
        for(i=1;i<=n;i++)
        {
            scanf("%d", &m);
            Sum=Sum+m;
        }
        return Sum;
    }
    int f3(short n)//使用do while()循环
    {
        int Sum=0;
        int m;
        short i=1;
        do{
            scanf("%d", &m);
            Sum=Sum+m;
            i++;
        }
        while(i<=n);
        return Sum;
    }
    int main()
    {
        short n;
        printf("1+2+...+n: \n");
        printf("Please input n: ");
        scanf("%hd", &n);
        if(n>=1&&n<=100)
        {
            printf("Sum=%d\n", f1(n));
            printf("Sum=%d\n", f2(n));
            printf("Sum=%d\n", f3(n));
        }
        else//n值不合法
        {
            printf("error!\n");
        }
        return 0;
    }

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