C标准时间与时间戳的相互转换

旧城等待， 2022-11-10 05:44 243阅读 0赞

话不多说，直接上代码;

#include <stdio.h>
    #include <string.h>
    #include <time.h>
    #include <stdlib.h>
    
    /*标准时间转换为时间戳*/
    int standard_to_stamp(char *str_time)
    { 
    	struct tm stm;
    	int iY,iM,iD,iH,iMin,iS;
    	memset(&stm,0,sizeof(stm));
    	iY = atoi(str_time);
    	iM = atoi(str_time+5);
    	iD = atoi(str_time+8);
    	iH = atoi(str_time+11);
    	iMin = atoi(str_time+14);
    	iS = atoi(str_time+17);
    	stm.tm_year=iY-1900;
    	stm.tm_mon=iM-1;
    	stm.tm_mday=iD;
    	stm.tm_hour=iH;
    	stm.tm_min=iMin;
    	stm.tm_sec=iS;
    	//printf("%d-%0d-%0d %0d:%0d:%0d\n", iY, iM, iD, iH, iMin, iS);
    
    	return (int)mktime(&stm);
    
    }
    
    /*时间戳转换为标准时间*/
    typedef struct times
    { 
    	int Year;
    	int Mon;
    	int Day;
    	int Hour;
    	int Min;
    	int Second;
    }Times;
    
    Times stamp_to_standard(int stampTime)
    { 
    	time_t tick = (time_t)stampTime;
    	struct tm tm;
    	char s[100];
    	Times standard;
    	tm = *localtime(&tick);
    	strftime(s, sizeof(s), "%Y-%m-%d %H:%M:%S", &tm);
    	printf("时间戳为：%d 转换成标准时间为： %s\n", (int)tick, s);
    
    	standard.Year = atoi(s);
    	standard.Mon = atoi(s+5);
    	standard.Day = atoi(s+8);
    	standard.Hour = atoi(s+11);
    	standard.Min = atoi(s+14);
    	standard.Second = atoi(s+17);
    	
    	return standard;
    }
    
    int main(int argc, char **argv)
    { 
    	int a =0;
    
    	printf("输入的标准时间时: %s \n",argv[1]);
    	
    	a=standard_to_stamp(argv[1]);
    	printf("标准时间转换为时间戳: %d\n",a);
    
    	stamp_to_standard(a);	
    
    	return  0;
    }

运行结果：  
![在这里插入图片描述][20210316174817646.png]

[20210316174817646.png]: /images/20221023/9d82d193c35c4bf9bfdd522c2fc4b447.png