日期范围 java_java – 日期范围中的日期范围

灰太狼 2022-11-06 08:59 152阅读 0赞

实际上这个任务对我来说似乎很容易,但我有点卡住了,并会感谢一些提示：D

我有一些开始和结束时间的事件 – 我想创建一个包含日历周的表格.

因此,我写了一个方法来检查一个事件是否在本周内为它着色如下：

private boolean inWeek(Date date, Entry pe) \{

return ((pe.getStartsAt().after(Util.firstDayOfWeek(date)) || pe.getStartsAt().equals(Util.firstDayOfWeek(date)))

&& (pe.getEndsAt().before(Util.lastDayOfWeek(date)) || pe.getEndsAt().equals(Util.lastDayOfWeek(date))));

如果事件持续一周,这个案子还可以.但如果事件在本周之前开始,或在本周之后结束甚至持续数周,该怎么办？

它变得非常复杂,我目前的解决方案是：

private boolean inWeek(Date date, Entry pe) \{

return ( pe.getStartsAt().after(Util.firstDayOfWeek(date)) && pe.getEndsAt().after(Util.firstDayOfWeek(date)) && pe.getEndsAt().before(Util.lastDayOfWeek(date)) )

|| ( pe.getStartsAt().before(Util.lastDayOfWeek(date)) && pe.getStartsAt().after(Util.firstDayOfWeek(date)) && pe.getEndsAt().after(Util.lastDayOfWeek(date)) )

|| ( pe.getStartsAt().after(Util.firstDayOfWeek(date)) && pe.getEndsAt().before(Util.lastDayOfWeek(date)) )

|| ( pe.getStartsAt().before(Util.firstDayOfWeek(date)) && pe.getEndsAt().after(Util.lastDayOfWeek(date)) );

但是仍然没有在某些细胞中显示正确的颜色.有人对我有任何暗示吗？

(…没有提议joda时间^^)

解决方法:

花了我相当多的时间来捣乱…好吧,时间……我可以告诉你,我宁愿让其他人为我做这项工作.

为此,如果你愿意试试,我会看看JodaTime

基本上,这个例子创建了一系列间隔.一个是“时期”,或一年中的一周(从星期一开始到星期日结束).

一个间隔是一个重叠间隔,跨越“周期”前一周和一周后,另一个是“周期”内的单日间隔

import org.joda.time.Interval;

import org.joda.time.MutableDateTime;

import org.joda.time.Period;

import org.joda.time.format.DateTimeFormat;

import org.joda.time.format.DateTimeFormatter;

import org.joda.time.format.DateTimeFormatterBuilder;

import org.joda.time.format.DateTimeParser;

public class TestTimeInterval \{

public static void main(String\[\] args) \{

DateTimeFormatter formatter = new DateTimeFormatterBuilder().

appendDayOfMonth(2).appendLiteral(" ").

appendDayOfWeekText().appendLiteral(" ").

appendMonthOfYearText().appendLiteral(" ").

appendYear(2, 2).

toFormatter();

// Last week

MutableDateTime targetStart = MutableDateTime.now();

targetStart.setDayOfWeek(1);

targetStart.addDays(-6);

// Next week

MutableDateTime targetEnd = MutableDateTime.now();

targetEnd.setDayOfWeek(7);

targetEnd.addDays(7);

System.out.println("Target range = " + formatter.print(targetStart) + " to " + formatter.print(targetEnd));

Interval targetInterval = new Interval(targetStart, targetEnd);

// This week

MutableDateTime start = MutableDateTime.now();

start.setDayOfWeek(1);

MutableDateTime end = MutableDateTime.now();

end.setDayOfWeek(7);

Interval interval = new Interval(start, end);

System.out.println("Interval range = " + formatter.print(start) + " to " + formatter.print(end));

System.out.println("Contains interval = " + targetInterval.contains(interval));

// Last week

targetStart = DateTime.now();

// Next week

targetEnd = DateTime.now();

System.out.println("Target range = " + formatter.print(targetStart) + " to " + formatter.print(targetEnd));

targetInterval = new Interval(targetStart, targetEnd);

System.out.println("Contains interval = " + interval.contains(targetInterval));

哪个输出……

Target range = 10 Tuesday December 2013 to 29 Sunday December 2013

Period range = 16 Monday December 2013 to 22 Sunday December 2013

Contains period = true

Target range = 19 Thursday December 2013 to 19 Thursday December 2013

Contains period = true

你最终只需要以两种方式检查周期间隔.

>检查“周期”是否在提供的间隔内

>如果提供的Interval在“期间”内……

例如…

if (period.contains(interval) || interval.contains(period)) \{

// Match...

现在,还有很多其他的事情要考虑,比如,如果时间间隔不重要,你会想要将时间归零(开始时间应该是午夜/早上,结束时间应该是午夜)所以你最大限度地捕获区域

更新了更好地使用JodaTime库

@BasilBourque能够突出显示原始示例中的一些问题,我已对其进行了更新和测试.谢谢@BasilBourque

虽然与原始类似,但它更好地使用JodaTime库

public static void newWay() \{

DateTimeFormatter formatter = new DateTimeFormatterBuilder().

appendDayOfMonth(2).appendLiteral(" ").

appendDayOfWeekText().appendLiteral(" ").

appendMonthOfYearText().appendLiteral(" ").

appendYear(2, 2).

toFormatter();

// Last week

DateTime targetStart = DateTime.now(DateTimeZone.getDefault()).

withDayOfWeek(DateTimeConstants.MONDAY).

minusDays(6);

//MutableDateTime targetStart = MutableDateTime.now();

//targetStart.setDayOfWeek(1);

//targetStart.addDays(-6);

// Next week

DateTime targetEnd = DateTime.now(DateTimeZone.getDefault()).

withDayOfWeek(DateTimeConstants.SUNDAY).

plusDays(7);

//MutableDateTime targetEnd = MutableDateTime.now();

//targetEnd.setDayOfWeek(7);

//targetEnd.addDays(7);

System.out.println("Target range = " + formatter.print(targetStart) + " to " + formatter.print(targetEnd));

Interval targetInterval = new Interval(targetStart, targetEnd);

// This week

DateTime start = DateTime.now(DateTimeZone.getDefault()).

withDayOfWeek(DateTimeConstants.MONDAY);

//MutableDateTime start = MutableDateTime.now();

//start.setDayOfWeek(1);

DateTime end = DateTime.now(DateTimeZone.getDefault()).

withDayOfWeek(DateTimeConstants.SUNDAY);

//MutableDateTime end = MutableDateTime.now();

//end.setDayOfWeek(7);

Interval interval = new Interval(start, end);

System.out.println("Period range = " + formatter.print(start) + " to " + formatter.print(end));

System.out.println("Contains period = " + targetInterval.contains(interval));

// Last week

targetStart = DateTime.now();

// Next week

targetEnd = DateTime.now();

System.out.println("Target range = " + formatter.print(targetStart) + " to " + formatter.print(targetEnd));

targetInterval = new Interval(targetStart, targetEnd);

System.out.println("Contains period = " + interval.contains(targetInterval));

标签：between,java,date,range

来源： https://codeday.me/bug/20190923/1813965.html

日期范围 java_java – 日期范围中的日期范围

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