Python高效编程技巧

你的名字 2022-10-19 12:44 207阅读 0赞

**1.控制台输出格式化的json数据**

使用python内置的json处理，可以使JSON串具有一定的可读性，但当遇到大型数据时，它表现成一个很长的、连续的一行时，人的肉眼就很难观看了。为了能让JSON数据表现的更友好，我们可以使用indent参数来输出漂亮的JSON。当在控制台交互式编程或做日志时，这尤其有用：

>>> import json
    >>> data = { "status": "OK", "count": 2, "results": [{ "age": 27, "name": "Oz", "lactose_intolerant": 'true'}, { "age": 29, "name": "Joe", "lactose_intolerant": 'false'}]}
    >>> print(json.dumps(data))  # No indention
    { "status": "OK", "count": 2, "results": [{ "age": 27, "name": "Oz", "lactose_intolerant": 'true'}, { "age": 29, "name": "Joe", "lactose_intolerant": 'false'}]}
    
    >>> print(json.dumps(data, indent=2))  # With indention
    { 
        "status": "OK",
        "count": 2,
        "results": [
            { 
                "age": 27,
                "name": "Oz",
                "lactose_intolerant": true
            },
            { 
                "age": 29,
                "name": "Joe",
                "lactose_intolerant": false
            }
        ]
    }

**2.同时迭代两个列表**

''' 遇到问题没人解答？小编创建了一个Python学习交流QQ群：531509025 寻找有志同道合的小伙伴，互帮互助,群里还有不错的视频学习教程和PDF电子书！ '''
    nfc = ["Packers", "49ers"]
    afc = ["Ravens", "Patriots"]
    for teama, teamb in zip(nfc, afc):
        print(teama + " vs. " + teamb)

**3.带索引的列表迭代**

teams = ["Packers", "49ers", "Ravens", "Patriots"]
    for index, team in enumerate(teams):
        print(index, team)

**4.列表转换成字符串**

''' 遇到问题没人解答？小编创建了一个Python学习交流QQ群：531509025 寻找有志同道合的小伙伴，互帮互助,群里还有不错的视频学习教程和PDF电子书！ '''
    teams = ["Packers", "49ers", "Ravens", "Patriots"]
    print(",".join(teams))

**5.查找元素中的所有组合**

from itertools import combinations
    teams = ["Packers", "49ers", "Ravens", "Patriots"]
    for game in combinations(teams, 2):
        print(game)
    
    
    ('Packers', '49ers')
    ('Packers', 'Ravens')
    ('Packers', 'Patriots')
    ('49ers', 'Ravens')
    ('49ers', 'Patriots')
    ('Ravens', 'Patriots')