去除对象中的原始值属性、引用值属性值为空的属性—

去除对象中的原始值属性、引用值属性值为空的属性——函数封装

在工作中，在调取接口时，经常需要往后端传递数据，如果后端那边没有对数据进行处理的话，则会因为一些空的数据导致接口调取失败。。

var obj = { "supplierId":0,"distributionChannel":null,"channelCount":0,"capacities":[{ "brandId":null,"leadTime":null,"payCondition":null}],"customers":[{ "name":null,"type":null,"brandName":null,"cooperationTime":null,"usedOfYear":null,"amount":null}],"productionDevices":[{ "name":null,"count":null}],"testingDevices":[{ "name":null,"count":null}],"artisanDevices":[{ "name":null,"count":null}],"honors":[{ "name":null,"year":2020,"picture":null,"issuingAuthority":null}],"staffs":[{ "name":null,"post":null,"characteristic":null,"background":null}],"talks":[{ "talkObject":null,"place":null,"organization":null,"companyPlanning":null,"productPlanning":null,"advantage":null,"shortcoming":null,"cooperation":null,"cooperationReason":null,"score":null,"scoreReason":null,"summary":null,"interviewer":null}]}

格式化一下，对象的结构如下：
在这里插入图片描述
注意这个对象中，有原始值也有数组格式的引用值，数据中的每一项又是对象格式的引用值。。

要把上面的对象将属性值为null的属性去掉的话，就需要循环遍历，去除null和""空字符串的函数封装如下：

function filterObj(obj) { 
  for (let key in obj) { 
      if (typeof obj[key] == 'object') { 
          if (Array.isArray(obj[key])) { 
              //数组
              obj[key].forEach((o, oIndex) => { 
                  for (let k in o) { 
                      if (o[k] == null || o[k] == "") { 
                          delete o[k];
                      }
                  }
                  if (o == { }) { 
                      obj[key].splice(oIndex, 1);
                  }
              })
          } else { 
              if (obj[key] == null || obj[key] == "") { 
                  delete obj[key];
              }
          }
      } else { 
          if (obj[key] == null || obj[key] == "") { 
              delete obj[key];
          }
      }
  }
  for (let k in obj) { 
      if (typeof obj[k] == 'object') { 
          if (Array.isArray(obj[k])) { 
              for (var i = 0; i < obj[k].length; i++) { 
                  if (Object.keys(obj[k][i]).length == 0) { 
                      obj[k].splice(i, 1);
                  }
              }
          }
      }
  }
  return obj;
}