android 选择文件并返回地址,在Android中实现文件选择器,并将选定的文件复制到另一个位置...

客官°小女子只卖身不卖艺 2022-10-14 01:12 265阅读 0赞

我试图在我的

Android项目中实现文件选择器.我迄今所能做的是：

Intent chooseFile;

Intent intent;

chooseFile = new Intent(Intent.ACTION\_GET\_CONTENT);

chooseFile.setType("\*/\*");

intent = Intent.createChooser(chooseFile,"Choose a file");

startActivityForResult(intent,PICKFILE\_RESULT\_CODE);

然后在我的onActivityResult()

switch(requestCode)\{

case PICKFILE\_RESULT\_CODE:

if(resultCode==-1)\{

Uri uri = data.getData();

String filePath = uri.getPath();

Toast.makeText(getActivity(),filePath,Toast.LENGTH\_LONG).show();

break;

这是打开一个文件选择器,但它不是我想要的.例如,我想选择一个文件(.txt),然后获取该文件,然后使用它.有了这个代码,我以为我会得到完整的路径,但不会发生;例如我得到：/ document / 5318 /.但是用这个路径我无法获取文件.我创建了一个名为PathToFile()的方法返回一个文件：

private File PathToFile(String path) \{

File tempFileToUpload;

tempFileToUpload = new File(path);

return tempFileToUpload;

我想要做的是让用户从任何地方选择一个文件,意思是DropBox,Drive,SDCard,Mega等…我没有找到正确的方法,我试图让路径然后得到一个文件由这个路径…但它不工作,所以我认为最好是获取文件本身,然后以该文件编程方式我复制此或删除.

编辑(当前代码)

我的意图

Intent chooseFile = new Intent(Intent.ACTION\_GET\_CONTENT);

chooseFile.addCategory(Intent.CATEGORY\_OPENABLE);

chooseFile.setType("text/plain");

startActivityForResult(

Intent.createChooser(chooseFile,"Choose a file"),PICKFILE\_RESULT\_CODE

);

在那里我有一个问题,因为我不知道什么是文本/简单的支持,但我会调查它,但这并不重要.

在我的onActivityResult()我使用与@Lukas Knuth answer相同,但我不知道是否可以复制该文件到我的SD卡的另一部分我正在等待他的答案.

@Override

public void onActivityResult(int requestCode,int resultCode,Intent data) \{

super.onActivityResult(requestCode,resultCode,data);

if (requestCode == PICKFILE\_RESULT\_CODE && resultCode == Activity.RESULT\_OK)\{

Uri content\_describer = data.getData();

//get the path

Log.d("Path???",content\_describer.getPath());

BufferedReader reader = null;

try \{

// open the user-picked file for reading:

InputStream in = getActivity().getContentResolver().openInputStream(content\_describer);

// now read the content:

reader = new BufferedReader(new InputStreamReader(in));

String line;

StringBuilder builder = new StringBuilder();

while ((line = reader.readLine()) != null)\{

builder.append(line);

// Do something with the content in

text.setText(builder.toString());

\} catch (FileNotFoundException e) \{

e.printStackTrace();

\} catch (IOException e) \{

e.printStackTrace();

\} finally \{

if (reader != null) \{

try \{

reader.close();

\} catch (IOException e) \{

e.printStackTrace();

getPath()from @ Y.S.

我在做这个：

String\[\] projection = \{ MediaStore.Files.FileColumns.DATA \};

Cursor cursor = getActivity().getContentResolver().query(content\_describer,projection,null,null);

int column\_index = cursor.getColumnIndexOrThrow(projection\[0\]);

cursor.moveToFirst();

cursor.close();

Log.d( "PATH-->",cursor.getString(column\_index));

得到一个NullPointerException：

java.lang.RuntimeException: Failure delivering result ResultInfo\{who=null,request=131073,result=-1,data=Intent \{ dat=file:///path typ=text/plain flg=0x3 \}\} to activity \{info.androidhive.tabsswipe/info.androidhive.tabsswipe.MainActivity2\}: java.lang.NullPointerException

这是我只接受文件/简单的意图.

Intent chooseFile = new Intent(Intent.ACTION\_GET\_CONTENT);

chooseFile.addCategory(Intent.CATEGORY\_OPENABLE);

chooseFile.setType("text/plain");

startActivityForResult(

Intent.createChooser(chooseFile,PICKFILE\_RESULT\_CODE

);

在我的onActivityResult()我创建一个URI,我获取Intent的数据,我创建一个文件,我保存绝对路径做content\_describer.getPath();然后我保留路径的名称在TextView with content\_describer.getLastPathSegment(); (这真的很棒@Y.S.不知道那个功能),我创建了一个第二个File,我称之为目标,我发送AbsolutePath可以创建这个文件.

@Override

public void onActivityResult(int requestCode,data);

if (requestCode == PICKFILE\_RESULT\_CODE && resultCode == Activity.RESULT\_OK)\{

Uri content\_describer = data.getData();

String src = content\_describer.getPath();

source = new File(src);

Log.d("src is ",source.toString());

String filename = content\_describer.getLastPathSegment();

text.setText(filename);

Log.d("FileName is ",filename);

destination = new File(Environment.getExternalStorageDirectory().getAbsolutePath() + "/Test/TestTest/" + filename);

Log.d("Destination is ",destination.toString());