android 重映射按键,Android SensorManager奇怪如何重映射CoordinateSystem

旧城等待， 2022-10-05 04:00 126阅读 0赞

API演示 - >图形 - > 指南针

它只能正常工作,直到您不更改设备的自然方向.在大多数手机中,肖像和大多数10英寸平板电脑是风景.如果你改变而不是需要旋转90度.我想看看该系统的3D修复.

我想看看如何(代码)如果我能看到如何计算那些轴映射(理论数学)的解释它会很好.

我试着理解,但我忘记了所有的线性代数.

这里说明为什么我们必须使用,但不告诉如何!

float R\[\] = new float\[9\];

// X (product of Y and Z) and roughly points East

// Y: points to Magnetic NORTH and tangential to ground

// Z: points to SKY and perpendicular to ground

float I\[\] = new float\[9\];

boolean success = SensorManager.getRotationMatrix(R, I, mGravity, mGeomagnetic);

似乎那些坐标是这个位置: - 设备在表格中说(x,y轴在桌子上)

![659c374d956b36d9cd341d1ff4fc8b73.png][]

只有,如果

getWindowManager().getDefaultDisplay().getRotation() == Surface.ROTATION\_0

问题是如何完成此代码: - 那些案例分支

switch (mScreenRotation) \{

case Surface.ROTATION\_0:

Log.v("SurfaceRemap", "0 degree");

axisX = SensorManager.AXIS\_X;// is this valid?

axisY = SensorManager.AXIS\_Y;// is this valid?

break;

case Surface.ROTATION\_90:

Log.v("SurfaceRemap", "90 degree");

// examples says remapCoordinateSystem(inR, AXIS\_Y, AXIS\_MINUS\_X, outR);

axisX = SensorManager.AXIS\_Y;

axisY = SensorManager.AXIS\_MINUS\_X;

break;

case Surface.ROTATION\_180:

Log.v("SurfaceRemap", "180 degree");

break;

case Surface.ROTATION\_270:

Log.v("SurfaceRemap", "270 degree");

break;

default:

Log.v("SurfaceRemap", "don't know the mScreenRotation value: "+mScreenRotation+" you should never seen this message!");

break;

boolean remapped = SensorManager.remapCoordinateSystem(R, axisX, axisY, R);

float orientation\[\] = new float\[3\];

SensorManager.getOrientation(R, orientation);// All three angles above are in radians and positive in the counter-clockwise direction.

inclination = SensorManager.getInclination(I);

编辑:我写了一个小测试应用程序,在屏幕上显示屏幕旋转:0,90,270度(现在不能180)

看来,如果Rotation 0不变(axisX = SensorManager.AXIS\_X;axisY = SensorManager.AXIS\_Y;),那么90度应该是:

axisX = SensorManager.AXIS\_MINUS\_Y;

axisY = SensorManager.AXIS\_X;

比谷歌文档说错误的值!问题在哪里？!

![edde1c3a6f1101ea203223f38b9357de.png][]

X被定义为矢量积YZ(它在器件的当前位置与地面相切并且大致指向东).

Y在器件的当前位置与地面相切,并指向磁北极.

Z指向天空并垂直于地面.

看到上面的手机!我想从左到右,后置摄像头到地面.

![d99ee7b7d2e5565e809fc847e9f0ce86.gif][]

X被定义为矢量积YZ(它在设备的当前位置与地面相切并且大致指向西).

Y在器件的当前位置与地面相切,并指向磁北极.

Z指向地球的中心并垂直于地面.

values\[0\]:方位角,绕Z轴旋转.

values\[1\]:俯仰,围绕X轴旋转.

values\[2\]:滚动,绕Y轴旋转.

怎么应该是手机？

最后我想拥有像飞机这样的角度值.我的电话(我)前往北方:(偏航是方位角)

![22fa02a76b996974198864710efefd98.png][]

if ScreenRotation = 0 degree

Pitch axis = -orientationAxisX = rotationAxisX

Roll axis = orientationAxisY = rotationAxisY

Yaw axis = orientationAxisZ = -rotationAxisZ

[659c374d956b36d9cd341d1ff4fc8b73.png]: /images/20221005/7fa9b3db95014be48dbff24a39014613.png
[edde1c3a6f1101ea203223f38b9357de.png]: /images/20221005/09c7a39545b1404ea8af7f6e004e8a7d.png
[d99ee7b7d2e5565e809fc847e9f0ce86.gif]: /images/20221005/1a8c6eede1b24dd9aea6ad2b3f8e7ea4.png
[22fa02a76b996974198864710efefd98.png]: /images/20221005/fc4e69b1287948f18c4659d6fdbcbe5d.png