C++实现大数相加 hdu

约定不等于承诺〃 2022-10-01 15:53 120阅读 0赞

[2019独角兽企业重金招聘Python工程师标准>>> ][2019_Python_] ![hot3.png][]

# c++实现大数相加，hdu1002解析 #

题目描述：

Problem Description
    I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
     
    
    Input
    The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
     
    
    Output
    For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
     
    
    Sample Input
    2
    1 2
    112233445566778899 998877665544332211
     
    
    Sample Output
    Case 1:
    1 + 2 = 3
    
    Case 2:
    112233445566778899 + 998877665544332211 = 1111111111111111110

#include <iostream>
    
    using namespace std;
    string CalculateTwoBigNum(string a,string b){
        int i,j,k;
        int a_Length = a.length();
        int b_Length = b.length();
        string BigerNum = a; //默认两个数字中更大为a
        string SmallerNum = b;
        if(a_Length<=b_Length){
            BigerNum = b;
            SmallerNum = a;
        }
        string result = BigerNum;
        for(i=BigerNum.length()-1,j=SmallerNum.length()-1;j>=0;i--,j--){
            result[i] = BigerNum[i] + SmallerNum[j]-'0';
        }
        for(k=BigerNum.length()-1;k>=0;k--){
            if(result[k]>'9'){
                result[k] = result[k]-10;
                if(k-1>=0){
                    result[k-1] =result[k-1]+1;
                }
                else
                    result = "1" + result;
            }
        }
        return result;
    }
    
    int main()
    {
        int Frequence; //计算次数
        string a,b; //参与计算的两个数
        string result; //计算结果
        cin>>Frequence;
        int Flag = 1; // case Flag
        while (Frequence--) {
            cin>>a>>b;
            result = CalculateTwoBigNum(a,b);
            printf("Case %d:\n",Flag++);
            cout<<a<<" + "<<b<<" = "<<result<<endl;
            if (Frequence>=1){
                cout<<endl;
            }
    
        }
        return 0;
    }

转载于:https://my.oschina.net/u/3444234/blog/3054430

[2019_Python_]: https://my.oschina.net/u/2663968/blog/3061697
[hot3.png]: /images/20220113/0f6a2f9157374b39b95cab3a23fa4e9e.png