[我眼中的C#]XML和JSON

分手后的思念是犯贱 2022-09-30 00:51 175阅读 0赞

**JSON**  
JSON式存储和交换文本信息的语法，它是一种轻量级文本数据交换格式，JSON独立于语言，他具有自我描述性，所以相对于XML更容易理解。  
学习JSON之前需要导入JSON 解析库，我们这里需要的是LitJSON.DLL，有两种方式导入  
1，直接去JSON官网从C\#模块下载，  
2，通过VS项目引用里的的NuGET直接联机下载。  
之后通过JSON创建两个json文档  
\{\}代表一个对象，而\[\]代表数组  
json主角信息.txt:  
\{  
“Name”:”siki”,  
“Level”:99,  
“Age”:18,  
“skilllist”:\[  
\{“id”: 2,”name”: “天下无双”,”demage”: 123\},  
\{“id”: 3,”name”: “独孤九剑”,”demage”: 56\},  
\{“id”: 4,”name”: “死亡之翼”,”demage”: 8003\}  
\]  
\}  
json技能信息.txt:  
\[  
\{“id”: 2,”name”: “天下无双”,”demage”: 123\},  
\{“id”: 3,”name”: “独孤九剑”,”demage”: 56\},  
\{“id”: 4,”name”: “死亡之翼”,”demage”: 8003\}  
\]  
在建立两个相关的类用来对应文档中的信息（注意对象名字一定要一样，不然搜索为空）  
Player.cs:

class Player
        {
            public string Name { get; set; }
            public int Level { get; set; }
            public int Age { get; set; }
            public List<Skill> skilllist { get; set; }
    
            public override string ToString()
            {
                return string.Format("Name: {0}, Level: {1}, Age: {2}", Name, Level, Age);
            }
        }

Skill.cs:

class Skill
        {
            public int id { get; set; }
            public int demage { get; set; }
            public string name { get; set; }
    
            public override string ToString()
            {
                return string.Format("id: {0}, demage: {1}, name: {2}", id, demage, name);
            }
        }

接着解析通过LitJson解析文档：

JsonData jsonData = JsonMapper.ToObject(File.ReadAllText("json技能信息.txt"));
                foreach (JsonData temp in jsonData)
                {
                    JsonData idValue = temp["id"]; //通过欧字符串索引器获取键值对的值
                    JsonData nameValueData = temp["name"];
                    JsonData damageValue = temp["demage"];
                    int id = int.Parse(idValue.ToString());
                    int demage = int.Parse(damageValue.ToString());
                    Console.WriteLine(id + " " + demage + " " + nameValueData);
                }
    
                Skill[] skillArray = JsonMapper.ToObject<Skill[]>(File.ReadAllText("json技能信息.txt"));//使用泛型解析Json
                foreach (var skill in skillArray)
                {
                    Console.WriteLine(skill);
                }
    
                List<Skill> skillArray = JsonMapper.ToObject<List<Skill>>(File.ReadAllText("json技能信息.txt"));
                foreach (var skill in skillArray)
                {
                    Console.WriteLine(skill);
                }
    
                Player player = JsonMapper.ToObject<Player>(File.ReadAllText("json主角信息.txt"));
                foreach (Skill skill in player.skilllist)
                {
                    Console.WriteLine(skill);
                }
                Console.WriteLine(player);
                Player p = new Player();
                p.Name = "sdf";
                p.Level = 16;
                p.Age = 18;
                string json = JsonMapper.ToJson(p);
                Console.WriteLine(json);
                Console.ReadKey();

**XML**  
XML文档解析过程与JSON类似，只不过后者采用了另一种语言以及解析方式  
FileText1.txt:

Skill.txt:

class Skill
        {
            public int Id { get; set; }
            public string EngName { get; set; }
            public int TriggerType { get; set; }
            public string ImageFile { get; set; }
            public string Name { get; set; }
            public int AvaliableRace { get; set; }
    
            public override string ToString()
            {
                return string.Format("Id: {0}, EngName: {1}, TriggerType: {2}, ImageFile: {3}, Name: {4}, AvaliableRace: {5}", Id, EngName, TriggerType, ImageFile, Name, AvaliableRace);
            }
        }

static void Main(string[] args)
            {
                List<Skill> skillLsit = new List<Skill>();
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load("TextFile1.txt");
                XmlNode skillInfoNode= xmlDoc.FirstChild;
                XmlNode skillListNode = skillInfoNode.FirstChild;
                XmlNodeList skillNode = skillListNode.ChildNodes;
                foreach (XmlNode mySkillNode in skillNode)
                {
                    Skill skill = new Skill();
                    XmlElement ele = mySkillNode["Name"];
                    skill.Name = ele.InnerText;
                    skill.Id = int.Parse(mySkillNode.Attributes["SkillID"].Value);
                    skill.EngName = mySkillNode.Attributes["SkillEngName"].Value;
                    skill.TriggerType = int.Parse(mySkillNode.Attributes["TriggerType"].Value);
                    skill.AvaliableRace = int.Parse(mySkillNode.Attributes["AvailableRace"].Value);
                    skill.ImageFile = mySkillNode.Attributes["ImageFile"].Value;
                    skillLsit.Add(skill);
                }
                foreach (var skill in skillLsit)
                {
                    Console.WriteLine(skill);
                }
                Console.ReadKey();
            }