codeforces 501B Misha and Changing Handles

比眉伴天荒 2022-09-24 10:18 12阅读 0赞

codeforces 501B - Misha and Changing Handles

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is already used or that was used at some point.

Misha has a list of handle change requests. After completing the requests he wants to understand the relation between the original and the new handles of the users. Help him to do that.

Input

The first line contains integer *q* (1 ≤ *q* ≤ 1000), the number of handle change requests.

Next *q* lines contain the descriptions of the requests, one per line.

Each query consists of two non-empty strings *old* and *new*, separated by a space. The strings consist of lowercase and uppercase Latin letters and digits. Strings *old* and *new* are distinct. The lengths of the strings do not exceed 20.

The requests are given chronologically. In other words, by the moment of a query there is a single person with handle *old*, and handle*new* is not used and has not been used by anyone.

Output

In the first line output the integer *n* — the number of users that changed their handles at least once.

In the next *n* lines print the mapping between the old and the new handles of the users. Each of them must contain two strings, *old* and*new*, separated by a space, meaning that before the user had handle *old*, and after all the requests are completed, his handle is *new*. You may output lines in any order.

Each user who changes the handle must occur exactly once in this description.

Examples

input

5
    Misha ILoveCodeforces
    Vasya Petrov
    Petrov VasyaPetrov123
    ILoveCodeforces MikeMirzayanov
    Petya Ivanov

output

3
    Petya Ivanov
    Misha MikeMirzayanov
    Vasya VasyaPetrov123

题目链接：[点击打开链接][Link 1]

代码：

#include<iostream>
    #include<stdio.h>
    #include<algorithm>
    #include<map>
    #include<string>
    using namespace std;
    
    map<string,int> old;
    map<string,string> link;
    map<string,int> num;
    
    string findlastname(string oldname)
    {
        while(num[oldname]!=1)
        {
            oldname=link[oldname];
        }
        return oldname;
    }
    
    int main()
    {
        int n;
        while(~scanf("%d",&n))
        {
            old.clear();
            link.clear();
            num.clear();
            while(n--)
            {
                string temp1,temp2;
                cin>>temp1>>temp2;
                old[temp1]++;
                link[temp1]=temp2;
                num[temp1]++;
                num[temp2]++;
            }
            int ans=0;
            map<string,int> ::iterator oldp;
            for(oldp=old.begin();oldp!=old.end(); oldp++)
            {
                if(oldp->second==1&&num[oldp->first]==1)
                {
                    ans++;
                }
            }
            cout<<ans<<endl;
            for(oldp=old.begin();oldp!=old.end(); oldp++)
            {
                if(oldp->second==1&&num[oldp->first]==1)
                {
                    cout<<oldp->first<<' '<<findlastname(link[oldp->first])<<endl;
                }
            }
        }
        return 0;
    }

[Link 1]: http://www.codeforces.com/contest/501/problem/B