【leetcode Database】181. Employees Earning More Than Their Managers

叁歲伎倆 2022-09-24 06:21 134阅读 0赞

题目:

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

  1. +----+-------+--------+-----------+
  2. | Id | Name | Salary | ManagerId |
  3. +----+-------+--------+-----------+
  4. | 1 | Joe | 70000 | 3 |
  5. | 2 | Henry | 80000 | 4 |
  6. | 3 | Sam | 60000 | NULL |
  7. | 4 | Max | 90000 | NULL |
  8. +----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

  1. +----------+
  2. | Employee |
  3. +----------+
  4. | Joe |
  5. +----------+

解析:本题可以使用自连接来做。声明Employee表的两个别名e1和e2,然后select e1的ManagerId字段与e2的Id字段相等,且e1的Salary大于e2的Salary。代码如下:

  1. # Write your MySQL query statement below
  2. SELECT e1.Name AS Employee FROM Employee AS e1,Employee AS e2 WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;

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