leetcode412Fizz Buzz

绝地灬酷狼 2022-09-04 12:42 22阅读 0赞

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80MTY3MjQwNA_size_16_color_FFFFFF_t_70]  
![在这里插入图片描述][3875e84edcc542498c4a10390352ab25.png]  
思路

1.  c语言里没有整数转字符串的，需要手动写，而且要反转一次
2.  注意i是从1开始的，数组是从0开始

代码

#include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    
    void exchange(char *s){ 
        int i=0,j = strlen(s)-1;
        while (i<j)
        { 
            char temp ;
            temp =s[i];
            s[i] =s[j];
            s[j] =temp;
            i++;j--;
        }
        
    }
    
    char * inttostring(int a){ 
        char *r = (char*)malloc(32);
        int i=0;
        if(a<0){ 
            r[i++] = '-';
        }
        while (a)
        { 
            int temp = a%10;
            r[i++] = temp+48;
            a= a/10;
        }
        r[i] = '\0';
        exchange(r);
        return r;
    }
    
    char ** fizzBuzz(int n, int* returnSize){ 
        char **re = (char **)malloc(sizeof(char*)*n);
        int i;
        for(i=0;i<n;i++)
            re[i] = (char*)malloc(n);
        for(i=1;i<=n;i++){ 
            if(i%3==0&&i%5==0)
                re[i-1] = "FizzBuzz";
            else if(i%5==0)
                re[i-1] = "Buzz";
            else if(i%3==0)
                re[i-1] = "Fizz";
            else
                re[i-1]=inttostring(i);
        }
        *returnSize = n;
        return re;
    }
    
    
    int main(){ 
        int a = 15;
        int size = 0;
        int i;
        char ** re = fizzBuzz(a,&size);
        for(i=0;i<size;i++)
            printf("%s\n",re[i]);  
    }

[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80MTY3MjQwNA_size_16_color_FFFFFF_t_70]: /images/20220829/0a9abb80ae6f4de6a463a74f7232cb6b.png
[3875e84edcc542498c4a10390352ab25.png]: /images/20220829/874c984502e64ca1a0b2c9fb544708c8.png