PTA 1005 Spell It Right (20 分)（详细翻译）

男娘i 2022-08-28 08:45 152阅读 0赞

# 背景： #

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

**给定一个非负整数N，你的任务是计算N中所有数字的和，并用英文输出这个和的每一位数字。**

# 输入格式： #

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

**每个输入文件包含一个测试用例。每种情况占用一行，其中包含一个N(<= 10100)。**

# 输出格式： #

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

**对于每个测试用例，在一行中输出英文单词表示的和的每一位数字。两个连续的单词之间必须有一个空格，但在这一行的末尾不能有额外的空格。**

# 输入样例： #

12345

# 输出样例： #

one five

# 思路： #

本题`不涉及`算法。

## C++实现代码： ##

#include <iostream>
    #include <vector>
    
    using namespace std;
    
    int main()
    { 
        vector<string> mp = {  "zero","one","two","three","four","five","six","seven","eight","nine" };
        string s;
        cin >> s;
        int sum = 0;
    
        for (decltype(s.length()) i = 0; i < s.length(); ++i)
            sum += (s[i] - '0');
    
        vector<int> ans;
        if (!sum)
            ans.push_back(0);
    
        while (sum)
        { 
            ans.push_back(sum % 10);
            sum /= 10;
        }
    
        for (int i = ans.size() - 1; i >= 0; --i)
        { 
            if (i == 0)
                cout << mp[ans[i]] << endl;
            else
                cout << mp[ans[i]] << " ";
        }
    
        return 0;
    }