编写程序检查某一个整数中是否有重复的数字

﹏ヽ暗。殇╰゛Y 2022-08-23 11:57 113阅读 0赞

/*
    编写程序检查某一个整数中是否有重复的数字,如检
    查2822中存在重复数字2
    */
    
    
    #include <stdio.h>
    
    int main(void)
    {
    	int n,i;
    	int num[10] = {0};
    	scanf("%d", &n);
    	do{
    		num[n%10]++;
    	
    	}while((n = n/10) != 0 );
    
    //	for(i = 0; i < 10; i++){
    //		printf("%d ", num[i]);
    //	}
    	for(i = 0; i < 10; i++){
    		if(num[i] >= 2){
    			printf("repeat\n");
    				break;
    		}
    	}
    	if(i == 10){
    		printf("no repeat\n");
    	}
    	
    
    
    	return 0;
    }
    /*
    akaedu@akaedu-G41MT-D3:~/lin/714_yiwei_shuzu$ ./3
    15699
    repeat
    akaedu@akaedu-G41MT-D3:~/lin/714_yiwei_shuzu$ ./3
    18362
    no repeat
    
    */
    
    //..........................................................
    /*#include <stdio.h>
    
    int main(void)
    {
    	unsigned n, digits[10] = {0};
    	scanf("%u", &n);
    	do{
    		if(digits[n%10])
    			break;
    		digits[n%10] = 1;
    	}while(n /= 10);
    
    	if(n > 0)
    		printf("Repeated\n");
    	else
    		
    		printf("Not Repeated\n");
    
    	return 0;
    }
    
    */

编写程序检查某一个整数中是否有重复的数字,如检
    查2822中存在重复数字2
    */
    /*
    改写上题,使其可以显示出哪些数字有重复。
    Enter a number: 939577
    Repeated digit(s) : 7 9
    */
    
    #include <stdio.h>
    
    int main(void)
    {
    	int n,i;
    	int num[10] = {0};
    	scanf("%d", &n);
    	do{
    		num[n%10]++;
    	
    	}while((n = n/10) != 0 );
    
    //	for(i = 0; i < 10; i++){
    //		printf("%d ", num[i]);
    //	}
    //	printf("\n");
    	for(i = 0; i < 10; i++){
    		if(num[i] >= 2){
    			printf("%d ", i);
    		}
    	}
    	printf("\n");
    	return 0;
    }<pre name="code" class="cpp">
    
    /*
    Enter a number: 939577
    Repeated digit(s) : 7 9
    写上题,使其打印一个列表,显示出每个数字在数
    中出现的次数:Enter a number: 41271092
    Digit :
    0 1 2 3 4 5 6 7 8 9
    Occurrences: 1 2 2 0 4 0 0 1 0 1
    */
    
    #include <stdio.h>
    
    int main(void)
    {
    	int n,i;
    	int num[10] = {0};
    	scanf("%d", &n);
    	do{
    		num[n%10]++;
    	
    	}while((n = n/10) != 0 );
    
    
    	printf("Disit:\n");
    	for(i = 0; i < 10; i++){
    		printf("%d ", i);
    	}
    	printf("\n");
    
    
    	printf("Occurrences:\n");
    	for(i = 0; i < 10; i++){
    		printf("%d ", num[i]);
    	}
    	printf("\n");
    
    	return 0;
    
    }
    
    
    /*
    12345656
    Disit:
    0 1 2 3 4 5 6 7 8 9 
    Occurrences:
    0 1 1 1 1 2 2 0 0 0 
    */