Java数组分隔成子数组

港控/mmm° 2022-08-19 14:11 163阅读 0赞

有这样一个需求，循环数组输出动态表单为一行两列  
分隔数组每两个为一组，如果单数最后一个为一组  
![这里写图片描述][20160119133249319]

import java.util.ArrayList;
    import java.util.List;
    
    public class SplitArray { 
        public static void main(String[] args) {
            String ary[] = { "a", "b", "c", "d", "e" }; // 分隔的数组
            int splitSize = 2; // 分隔的大小
    
            Object subAry[] = splitAry(ary, splitSize);
            for (Object obj : subAry) {
                String subItem[] = (String[]) obj;
                for (int i = 0; i < subItem.length; i++) {
                    System.out.print(subItem[i] + ",");
                }
                System.out.println();
            }
        }
    
        /** * 比如 { "a", "b", "c", "d", "e" } * 分隔成 * a, b * c, d * e */
        private static Object[] splitAry(String ary[], int subSize) {
    
            int count = ary.length % subSize == 0 ? ary.length / subSize
                    : ary.length / subSize + 1;
    
            List<List<String>> subAryList = new ArrayList<List<String>>();
            for (int i = 0; i < count; i++) {
                int index = i * subSize;
                List<String> list = new ArrayList<String>();
                int j = 0;
                while (j < subSize && index < ary.length) {
                    list.add(ary[index++]);
                    j++;
                }
                subAryList.add(list);
            }
            // 将List<List<String>> 封装为 Object[],也可以不需要
            Object[] subAry = new Object[subAryList.size()];
            for (int i = 0; i < subAryList.size(); i++) {
                List<String> subList = subAryList.get(i);
                String[] subAryItem = new String[subList.size()];
                for (int j = 0; j < subList.size(); j++) {
                    subAryItem[j] = subList.get(j);
                }
                subAry[i] = subAryItem;
            }
            return subAry;
        }
    }

作者：[itmyhome][]

[20160119133249319]: /images/20220731/19aef8ff029f46008d06725ea32eb3c7.png
[itmyhome]: http://blog.csdn.net/itmyhome1990